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SSSSS [86.1K]
2 years ago
5

Later in this course we will learn how to combine flip-flops to make transitions to desired outputs. The flip-flop is holding bi

t of information, waiting for a signal to change (memory). But in this example YOU are still making the transition by flipping a switch. How can we make the flip-flop change without us providing the input directly
Engineering
1 answer:
expeople1 [14]2 years ago
8 0

Answer:

Clock input( or Timer Oscillator)   in used to change the state of the output.  

Explanation:

Flip-flop is an device that is the state changes with the rising or falling of the clock. It has a control signal (clock) input that stores the input state and outputs the state only in response to the clock signal.

The output changes with the change in the input in synchronization with the clock.  

Whenever the input of the clock changed, it will result in change in the output.

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The following passage contains a fragment. Select the correct revision. Presley took the exuberance of gospel and added the freq
Semmy [17]

Answer:

A

Explanation:

Option A was the only option that did not have a sentence fragment. All the other choices were fragments because they interrupted the flow of the sentence. A sentence fragment means that if you started reading where the period is, you would understand everything about the sentence and it would be clear. You cannot have an incomplete sentence that does not have background information. An example would be: And that is how you install it. This leaves information unanswered, such as what the subject of the sentence is, or in other words, what you were installing. Another indicator that this was a sentence fragment was that the sentence began with the word "And." Sentence fragments very commonly start with the word and, because that word shows that it is a continuation of a topic.

7 0
2 years ago
The uniform 8–ft board is pushed down into the water so it makes an angle of θ = 30o with the water surface. If the cross sectio
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Answer:

The vertical force, F = 19.9 lb.

Explanation:

3 0
2 years ago
A steady tensile load of 5.00kN is applied to a square bar, 12mm on a side and having a length of 1.65m. compute the stress in t
Shtirlitz [24]

Answer:

The stress in the bar is 34.72 MPa.

The design factor (DF) for each case is:

A) DF=0.17

B) DF=0.09

C) DF=0.125

D) DF=0.12

E) DF=0.039

F) DF=1.26

G) DF=5.5

Explanation:

The design factor is the relation between design stress and failure stress. In the case of ductile materials like metals, the failure stress considered is the yield stress. In the case of plastics or ceramics, the failure stress considered is the breaking stress (ultimate stress). If the design factor is less than 1, the structure or bar will endure the applied stress. By the opposite side, when the DF is higher than 1, the structure will collapse or the bar will break.

we will calculate the design stress in this case:

\displaystyle \sigma_{dis}=\frac{T_l}{Sup}=\frac{5.00KN}{(12\cdot10^{-3}m)^2}=34.72MPa

The design factor for metals is:

DF=\displaystyle \frac{\sigma_{dis}}{\sigma_{f}}=\frac{\sigma_{dis}}{\sigma_{y}}

The design factor for plastic and ceramics is:

DF=\displaystyle \frac{\sigma_{dis}}{\sigma_{f}}=\frac{\sigma_{dis}}{\sigma_{u}}

We now need to know the yield stress or the ultimate stress for each material. We use the AISI and ASTM charts for steels, materials charts for non-ferrous materials and plastics safety charts for the plastic materials.

For these cases:

A) The yield stress of AISI 120 hot-rolled steel (actually is AISI 1020) is 205 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{205MPa}=0.17

B) The yield stress of AISI 8650 OQT 1000 steel is 385 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{385MPa}=0.09

C) The yield stress of ductile iron A536-84 (60-40-18) is 40Kpsi, this is 275.8 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{275.8MPa}=0.125

D) The yield stress of aluminum allot 6061-T6 is 290 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{290MPa}=0.12

E) The yield stress of titanium alloy Ti-6Al-4V annealed (certified by manufacturers) is 880 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{880MPa}=0.039

F) The ultimate stress of rigid PVC plastic (certified by PVC Pipe Association) is 4Kpsi or 27.58 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{27.58 MPa}=1.26

In this case, the bar will break.

F) You have to consider that phenolic plastics are used as matrix in composite materials and seldom are used alone with no reinforcement. In this question is not explained if this material is reinforced or not, therefore I will use the ultimate stress of most pure phenolic plastics, in this case, 6.31 MPa:

DF=\displaystyle\frac{34.72MPa}{6.31 MPa}=5.5

This material will break.

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2 years ago
A heat recovery device involves transferring energy from the hot flue gases passing through an annular region to pressurized wat
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Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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