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sergeinik [125]
2 years ago
4

A sinusoidal wave moving to the left has a wavelength of 5.0 cm and a frequency of 50 Hz. At t = 0 s, the wave has a crest at x

= 0 cm. What is the earliest time after t = 0 s at which there is a crest at the position x = 3.5 cm?
Physics
1 answer:
Varvara68 [4.7K]2 years ago
7 0

Answer:

0.006 seconds

Explanation:

Were are told that:

At t = 0 s, the wave has a crest at x = 0 cm.

The distance between two consecutive wavelength ( λ ) given by the sinusoidal wave = 5.0 cm

And; Velocity can be expressed as: fλ

where f = 50 Hz

Velocity (V) = 50 × 5.0

V = 250 cm/s

If the crest is moved to a distance of 5.0 cm to 3.5 cm; then the distance traveled = (5.0 - 3.5) cm

= 1.5 cm

However; the earliest time (t) by the wave will be : \frac{1.5}{250} = 0.006 seconds

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three point charges are positioned on the x-axis 64 uc at x=ocm , 80uc at x=25cm, and -160 uc at x=50 cm. what is the magnitude
LekaFEV [45]

Answer:

The magnitude of the electrostatic force is F = 368.64 N

Explanation:

Given data,

The magnitude of charge, q₁ = 64 μ C

The magnitude of charge, q₂ = 80 μ C

The magnitude of charge, q₃ = -160 μ C

The charge q₁ is at the origin,

The position of charge q₁ in x-axis, x₁ = 0 cm

The position of charge q₂ in x-axis, x₂ = 25 cm

                                                               = 0.25 m

The position of charge q₃ in x-axis, x₃ = 50 cm

                                                               = 0.5 m

The magnitude of the electrostatic force experienced by the charge a is given by the formula,

The force acting on charge 'q₁' due to 'q₂' is,

                             F₁ = k  q₁ q₂ / x₂²

                                 = (9 x 10⁹ X 64 x 10⁻⁶ X 80 x 10⁻⁶) / 0.25²

                                =  + 737.28 N

The force acting on charge 'q₁' due to 'q₃' is,

                              F₂ = k q₁ q₃ / x₃²

                                   = [9 x 10⁹ X 64 x 10⁻⁶ X (-160 x 10⁻⁶)] / 0.5²

                                    = - 368.64 N

The net electrostatic force acting on the charge, q₁ is,

                              F = F₁ + F₂

                                  = + 737.28 N + (- 368.64 N)

                                   = 368.64 N

Hence, the magnitude of the electrostatic force is F = 368.64 N

6 0
2 years ago
A diver is is pushed upwards by a diving board. She weighs 739 N and accelerates from rest to a speed of 4.60 m/s while moving 0
gavmur [86]

Answer:

Answer A

Explanation:

It seems more likely

8 0
2 years ago
Under which one of the following circumstances will heat transfer occur via convection? Group of answer choices Convection occur
BartSMP [9]

Answer:

1) in metal object heat transfer through the conduction .In vacuum heat transfer through only radiation .

In only gaseous state or in liquid state the heat transfer through convection hence option D is correct

8 0
2 years ago
Read 2 more answers
In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law t
RSB [31]

Answer:

The answers and workings is in the Explanation section

Explanation:

<em>In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law the current through the circuit is _____________ Amps. </em>

According to Ohm’s law V =I*R  

Where V = Voltage, I = Current and R = Resistance

I = V/R =6/3 =2 Amps of current

Answer = 2 Amps

<em> If a second identical lamp is connected in series, the 6-volt battery must push a charge through a total resistance of ________ Ω</em>.  <em>The current in the circuit is then __________ Amps. </em>

Since the second lamp is connected in series with the first, the total resistance will R₂ = 3 + 3 = 6Ω

2 resistance in series  R₂ =  6Ω

The current in the circuit with the two lamps connected in series is I₂ =V/R₂ =6/6 = 1 Amps

The current is 1 Amps

Answer =  6Ω  and 1 Amps

<em>If a third identical lamp is connected in series, the total resistance is now _________Ω.  The current through all three lamps in series is now _________ Amps.  </em>

Since the third lamp is connected in series with the first and second, the total resistance will R₃ = 3 + 3 + 3 = 9Ω

total resistance of the 3 lamps R₃ =  9Ω

The current in the circuit with the three lamps connected in series is

I =V/R₃ =6/9 = 0.67 Amps

The current through the 3 lamps I₃ = 0.67 Amps

Answer =  9Ω  and 0.67 Amps

<em>The current through each individual lamp is __________ Amps.  </em>

Since all 3 lamps are connected in series, the same current will flow through each of the  3 lamps, and that current is I₃  

The current through each individual lamp is 0.67 Amp

Answer = 0.67 Amp

<em>What is the power when a voltage of 120 volts drives a current of 3 amps through a device?  </em>

The formula for power P = I*V =120*3 = 360 Watts

power P  = 360 Watts

Answer = 360 Watts

<em>What is the current when a 90-W light bulb is connected to 120 V? </em>

From P =I*V, make I the subject of the formula, I = P/V =90/120 = 0.75

Current= 0.75 Amps

Answer =  0.75 Amps

<em>How much current does a 75-W light bulb draw when connected to 120 V?</em>  

Current I =P/V = 75/120 = 0.625 Amps.

Answer = 0.625 Amps

<em>If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it? </em>

Voltage V =P/I =6/3 =2 Volts

Answer = 2 Volts

<em> If a 60 W light bulb at 120 V is left on in your house to prevent burglary, and the power company charges 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days? Show your work. </em>

24 hours make 1 day, so the number of hours the bulb was left on = 24 *30 = 720 hours

The power rating of the bulb is 60W = 60/1000 = 0.06 KiloWatt

Total power consumed in kilowatt-hour = 0.06 * 720 = 43.2 kilowatt-hour

Cost for 30 days = 0.1*43.2 = $4.32 ( note that 10 Cents = $0.1)

Answer =  $4.32

4 0
2 years ago
A 15.0 kg load of bricks hangs from one end of a rope that passes over a small, frictionles pulley. A 28.0 kg counterweight is s
Talja [164]

Answer:

A) The free body diagrams for both the load of bricks and the counterweight are attached.

B) a = 2.96 m/s²

Explanation:

A)

The free body diagrams for both the load of bricks and the counterweight are attached.

B)

The acceleration of upward acceleration of the load of bricks is given by the following formula:

a = g(m₁ - m₂)/(m₁ + m₂)

where,

a = upward acceleration of load of bricks = ?

g = 9.8 m/s²

m₁ = heavier mass = mass of counterweight = 28 kg

m₂ = lighter mass = mass of load of bricks = 15 kg

Therefore, using these values in equation, we get:

a = (9.8 m/s²)(28 kg - 15 kg)/(28 kg + 15 kg)

<u>a = 2.96 m/s²</u>

3 0
2 years ago
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