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kondor19780726 [428]
2 years ago
14

Tony uses the device shown in the diagram to model how an electromagnet is used in his uncle’s scrap metal yard. After picking u

p several staples with the device, what change would enable Tony to drop the staples in the scrap metal bin?
Removing the battery
removing the iron nail
moving the wire loops closer together
spreading the wire loops farther apart
Physics
2 answers:
marusya05 [52]2 years ago
8 0
An electromagnet is a device which uses a current and passes this through a conductor. The current induces a magnetic field in the conductor, making the conductor a magnet. In order to remove the effects of this magnetism, the device may have its electrical power cut off. Therefore, the way to drop the staples in the bin would be to remove the battery.
PolarNik [594]2 years ago
7 0

for the ones on edge its a

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What volume in milliliters will 0.00922 g of h2 gas occupy at stp?
Nadusha1986 [10]
Assuming that this gas is in ideal state, we can use the relation that for every 1 mol of an ideal gas it would have a volume of 22.4 L. But before using this, relation we need to convert the number of grams of H2 into moles by using the molar mass of 2.02 g/mol.

moles H2 = 0.00922 g ( 1 mol / 2.02 g ) = 0.005 mol H2

Volume H2 at STP = 0.005 mol H2 ( 22.4 L / 1 mol ) = 0.102 L of H2
4 0
2 years ago
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
dlinn [17]

Answer:

a = 4.72 m/s²  

Explanation:

given,

mass of the box (m)= 6 Kg

angle of inclination (θ) = 39°

coefficient of kinetic friction (μ) = 0.19

magnitude of acceleration = ?

box is sliding downward so,

F - f = m a                        

f is the friction force

m g sinθ - μ N = ma                        

m g sinθ - μ m g cos θ = ma            

a = g sinθ - μ g cos θ                    

a = 9.8 x sin 39° - 0.19 x 9.8 x cos 39°

a = 4.72 m/s²                                      

the magnitude of acceleration of the box down the slope is a = 4.72 m/s²  

3 0
2 years ago
"As the Voyager spacecraft penetrated into the outer solar system, the illumination from the Sun declined. Relative to the situa
____ [38]

Answer:

\frac{I_{2}}{I_{1}} = 0.04

Explanation:

The intensity of a star noticed at a certain distance is inversely proportional to the square of distance. Then:

I_{1}\cdot r_{1}^{2} = I_{2}\cdot r_{2}^{2}

The intensity of the Sun in Jupiter relative to Earth is:

\frac{I_{2}}{I_{1}} = \frac{r_{1}^{2}}{r_{2}^{2}}

\frac{I_{2}}{I_{1}} = \left(\frac{1\,AU}{5.2\,AU} \right) ^{2}

\frac{I_{2}}{I_{1}} = 0.04

3 0
2 years ago
A 15-kg block at rest on a horizontal frictionless surface is attached to a very light ideal spring of force constant 450 N/m. T
den301095 [7]

Answer:

0.266 m

Explanation:

Assuming the lump of patty is 3 Kg then applying the principal of conservation of linear momentum,

P= mv where p is momentum, m is mass and v is the speed of an object. In this case

m_pv_p=v_c(m_p+m_b) where sunscripts p and b represent putty and block respectively, c is common velocity.

Substituting the given values then

3*8=v(15+3)

V=24/18=1.33 m/s

The resultant kinetic energy is transferred to spring hence we apply the law of conservation of energy

0.5(m_p+m_b)v_c^{2}=0.5kx^{2} where k is spring constant and x is the compression of spring. Substituting the given values then

(3+15)*1.33^{2}=450*x^{2}\\x\approx 0.266 m

7 0
2 years ago
A ball is thrown through the air.What condition(s) would enable the ball to continue in its state of motion?
Aleksandr-060686 [28]
I think that the answer is c but I’m not sure
5 0
2 years ago
Read 2 more answers
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