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2 years ago

How can promoting total person development can benefit an organization.

Physics

2 answers:

Alex787 [66]2 years ago

5 0

Promoting total person development can benefit an organization in the following way

Explanation:

1.Promoting personal development in the workplace

All images courtesy of Forbes Councils members.
Create Growth Plans. ...
Build In 'Growth Time' ...
Set 90-Day Learning Goals. ...
Offer Innovative Learning Experiences. ...
Map Out The Far-Reaching Benefits. ...
Make Development Opportunities 'One Size Fits One' ...
Take An Active Interest In Personal Development. ...
Think Beyond Formal Training.

2. Create a development plan. Help your employees establish goals that are aligned with their strengths, interest and experience, as well as with the overall business strategy. Establish goals and expectations to help them set their sights on career opportunities.

3. 7 Things Every Great Boss Should Do

Acknowledge. When things are going well in your organization, let people know--early and often. ...
Motivate.
Communicate. Communicate clearly, professionally, and often. ...
Trust. Learn to trust your employees. ...
Develop. Set up your employees for success, not failure. ...
Direct.
Partner.

4.Human relations skills such as communication and handling conflict can help us create better relationships. ... Since many companies' organizational structures depend upon people working together, positive human relations skills reduce conflict in the workplace, thereby making the workplace more productive.

5.Improves effectiveness in business

In business, personal development improves effectiveness. It empowers staff to produce better results and meet their targets. For excellent results, an employer or a business owner must have an energetic and a productive team.

mel-nik [20]2 years ago

5 0

Promoting the person development works as a motivation to work harder and with more efficiency to achieve the goals of the organisation.

<u>Explanation:</u>

Human relations abilities, for example, correspondence and dealing with struggle can assist us with making better connections. Since numerous organizations' authoritative structures rely on individuals cooperating, positive human relations aptitudes lessen strife in the working environment, subsequently making the work environment more productive.

Opportunities for development and improvement assist representatives with growing their insight, abilities and capacities, and apply the capabilities they have picked up to new circumstances.

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The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371

arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

$q=m\times c\times (T_2-T_1)$

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = $4.18J/g.K$

$T_1$ = initial temperature of water = 293.0 K

$T_2$ = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

$q=250g\times 4.18J/g.K\times (371.2-293.0)K$

$q=81719J$

Now we have to calculate the enthalpy of combustion of octane.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

$\Delta H=\frac{-81719J}{0.015mole}$

$\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol$

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0

2 years ago

Of waterfalls with a height of more than 50 m , Niagara Falls in Canada has the highest flow rate of any waterfall in the world.

Vinil7 [7]

Answer:

Power output: W=1426.9MW

Explanation:

The power output of the falls is given mainly by its change in potential energy:

$Q=-P_{tot}=-(P_{2}-P_{1})$

The potential energy for any point can be calculated as:

$P=m*g*h$

If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:

$Q=P_{1}=m*g*h$

If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:

$W=M*g*h=2.8*10^{3}m^{3}/s*1*10^{3}kg/m^{3}*9.8m/s^{2}*52m =1426.9MW$

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2 years ago

Object A of mass M is moving east at speed v. It collides with object B of mass 2M that was initially at rest. The motion of the

Firlakuza [10]

Answer:

$v_B=\frac{v}{3}$

Explanation:

Given that:

mass of object A, $m_A=M$

mass of object B, $m_B=2M$

speed of object A, $v_A=v$

So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.

$m_A.v+m_B\times 0=m_A\times v_A +m_B\times v_B$

$M\times v+0 = M\times \frac{v}{3}+2M\times v_B$

$2M\times v_B= \frac{2M\times v}{3}$

$v_B=\frac{v}{3}$

3 0

2 years ago

A circuit is made of 0.4 ohm wire, 150 ohm bulb and a 120ohm rheo stat connected inseries. Determine the total resistance of the

UNO [17]

Answer:
Total resistance of the circuit is 270.4 ohm

Explanation:
We are given that:
resistance of wire = 0.4 ohm
resistance of bulb = 150 ohm
resistance of rheostat = 120 ohm

We are also given that these components are connected in series. This means that the total resistance is summation of all the series components.

Therefore
Total resistance = 0.4 + 150 + 120 = 270.4 ohm

Hope this helps :)

8 0

2 years ago

Nora tied a string around a tennis ball, and then she swung it in a circle in front of her to demonstrate a planet orbiting the

777dan777 [17]

<em>Choice-A </em>is a true statement. The string holding the ball in orbit is a contact force, whereas gravity is a non-contact force.

Choice-C is half-true. The string keeps the distance between the bodies constant, but gravity doesn't "MAKE" the distance vary.

8 0

1 year ago

Read 2 more answers