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sp2606 [1]
2 years ago
15

An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

bject suspended from it. Assume a wire of mass 4.00 g is 1.60 m long and has a 3.00-kg object suspended from it. A pulse requires 65.6 ms to traverse the length of the wire. Calculate gplanet from these data. (You may neglect the mass of the wire when calculating the tension in it.)
Physics
1 answer:
8_murik_8 [283]2 years ago
7 0

Answer:

The gplanet is 0.193 m/s^2

Explanation:

The speed of the pulse is:

v=\frac{lengthofthewipe}{traveltime} =\frac{1.6}{0.0656} =15.24m/s

v=\sqrt{\frac{MgL}{m} } \\v^{2} =\frac{MgL}{m} \\g=\frac{mv^{2} }{ML}

where

m=mass of the wire=4 g= 4x10^-3 kg

M=mass of the object= 3 kg

Replacing values:

g=\frac{4x10^{-3}*15.24^{2}  }{3*1.6} =0.193 m/s^{2}

You might be interested in
A plane has an average air speed (this is the speed the plane moves through air) of 750 mph. The plane flies a route of 5000 mil
Digiron [165]

Answer:

6 hours 15 minutes

Explanation:

On the trip from L.A. to London, the plane travels at 750 mph against a headwind of 50 mph, and that makes the net 700 mph (in aviation speak, 750 is the airspeed, while 700 is the groundspeed).  5000 miles divided by 700 mph results in about 7.14 hours, or about 7 hours and 9 minutes.  On the return trip, ASSUMING THE SAME WIND, the plane travels at 750 mph, but this time the wind of 50 mph is a tail wind.  So the net (groundspeed) is 800 mph.  Traveling 5000 miles at 800 mph only takes 6.25 hours, or 6 hours and 15 minutes.  

Outbound flight 7 hours 9 minutes

Return flight 6 hours 15 minutes

6 0
1 year ago
An American manufacturer supplied a customer with refrigerators with electrical cords that were one yard long instead of 1 meter
Simora [160]

Answer:

C.

Explanation:

A meter is 8.56 centimeters longer than a yard. Something to keep in mind is that a meter is about 10% longer than a yard.

Hope this helps :)

6 0
1 year ago
Read 2 more answers
Sarah is 14 years old and skips school twice a week without any written explanation. What can she be charged with?
harina [27]

Answer:

Too many people are unaware or indifferent to that.” Fines can cost up to $500 per truancy, due within 30 days unless a judge gives an extension. For many students and families, it's another debt they can't pay. And if fines aren't paid, they can convert into an arrest warrant when a student turns 17.

Explanation:

5 0
2 years ago
Find the kinetic of a 0.1 kilogram toy truck moving at a speed of 1.1 meters per second
omeli [17]
KE = kinetic energy
PE = potential energy
GPE = gravitational potential energy
energy is always measured in Joules (J)

KE = (0.5) times the mass times the velocity^2
square the velocity first

Mass = (KE x 2) / v^2
square the velocity first, then double the kinetic energy, then divide
mass is measured in kg

velocity = sqrt(KE x 2 / m)
velocity can be called speed, like in the the second problem
remember to find the square root after you double the KE and divide that by the mass.
for example: if after you doubled KE and divided it by the mass you got sqrt(20), the answer would be about 4.47

GPE = mass x gravitational pull (about 9.8 m/s^2 on earth) x height

height = (PE) / (g x m)
do g x m first

So for question 1:
KE = (0.5)0.1 x 1.1^2
always square the velocity first:
KE = (0.5)0.1 x 1.21
KE = 0.0605
so if you rounded it to the nearest hundreths you would get KE = 0.06 J
don't forget the unit of energy is in Joules
5 0
1 year ago
A person pushes horizontally on a 50-kg crate, causing it to accelerate from rest and slide across the surface. If the push caus
Marina CMI [18]

Answer:

v_{f} =4.9\frac{m}{s}  :  velocity of the crate after the person has pushed the crate a distance of 6 meters

Explanation:

Crate kinetics

Crate moves with uniformly accelerated movement

v f²=v₀²+2a*d (formula 1)

d:displacement in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Known data

v₀=0 The speed of the crate is equal to zero because part of the rest.

a= 2m/s²

d= 6m

Distance calculating

We replace data in the Formula (1)

v f²=0+2*2*d

v f²=2*2*6

v f²=24

v_{f} =\sqrt{24}

v_{f} =4.9\frac{m}{s}

7 0
2 years ago
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