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2 years ago

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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

bject suspended from it. Assume a wire of mass 4.00 g is 1.60 m long and has a 3.00-kg object suspended from it. A pulse requires 65.6 ms to traverse the length of the wire. Calculate gplanet from these data. (You may neglect the mass of the wire when calculating the tension in it.)

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:

The gplanet is 0.193 m/s^2

Explanation:

The speed of the pulse is:

$v=\frac{lengthofthewipe}{traveltime} =\frac{1.6}{0.0656} =15.24m/s$

$v=\sqrt{\frac{MgL}{m} } \\v^{2} =\frac{MgL}{m} \\g=\frac{mv^{2} }{ML}$

where

m=mass of the wire=4 g= 4x10^-3 kg

M=mass of the object= 3 kg

Replacing values:

$g=\frac{4x10^{-3}*15.24^{2} }{3*1.6} =0.193 m/s^{2}$

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6000

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Answer:

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