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2 years ago

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An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

bject suspended from it. Assume a wire of mass 4.00 g is 1.60 m long and has a 3.00-kg object suspended from it. A pulse requires 65.6 ms to traverse the length of the wire. Calculate gplanet from these data. (You may neglect the mass of the wire when calculating the tension in it.)

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:

The gplanet is 0.193 m/s^2

Explanation:

The speed of the pulse is:

$v=\frac{lengthofthewipe}{traveltime} =\frac{1.6}{0.0656} =15.24m/s$

$v=\sqrt{\frac{MgL}{m} } \\v^{2} =\frac{MgL}{m} \\g=\frac{mv^{2} }{ML}$

where

m=mass of the wire=4 g= 4x10^-3 kg

M=mass of the object= 3 kg

Replacing values:

$g=\frac{4x10^{-3}*15.24^{2} }{3*1.6} =0.193 m/s^{2}$

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Answer:

Therefore,

Current through Nichrome wire is 0.3879 Ampere.

Explanation:

Given:

Length = l = 10 meter

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To Find:

Current, I =?

Solution:

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Where,

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Substituting the values we get

$R=\dfrac{1\times 10^{-6}\times 10}{3.14\times (0.321\times 10^{-3})^{2}}$

$R=\dfrac{1\times 10^{-5}}{3.23\times 10^{-7}}$

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Now by Ohm's Law,

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$I=\dfrac{V}{R}=\dfrac{12}{30.95}=0.3876\ Ampere$

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2 years ago

When a pendulum is pulled back from its equilibrium position by 10∘, the restoring force is 1.0 N. When it is pulled back to 30∘

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Answer: B

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Answer:

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Because of change in charge accumulation with time above the plates, the electric field changes causing the displacement current.

Displacement current arises due to the flow of electrons as a result of the varying magnetic fields set up on the plates of the capacitor when supplied with an AC voltage. It is important to note that a DC voltage does not induce any displacement current.

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A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kgÂ·m2. If the arms are pulled in so t

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$K=\frac{1}{2}I\omega^2$

where

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