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Marizza181 [45]
2 years ago
14

Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 276 mL .

Chemistry
1 answer:
garri49 [273]2 years ago
5 0
Mass = ?

Density = 2.70 g/mL

Volume = 276 mL

Therefore:

D = m / V

2.70 = m / 276

m = 2.70 x 276

m = 745.2 g

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A certain element X has four isotopes. 4.350% of X has a mass of 49.94605 amu. 83.79% of X has a mass of 51.94051 amu. 9.500% of
sesenic [268]

Answer: The average atomic mass of the element X is 51.99592 amu

Explanation:

Mass of isotope 1 = 49.94605 amu

% abundance of isotope 1 = 4.350% = \frac{4.350}{100}=0.0435

Mass of isotope 2 = 51.94051 amu.

% abundance of isotope 2 = 83.79% = \frac{83.79}{100}=0.8379

Mass of isotope 3 = 52.94065 amu.

% abundance of isotope 2 = 9.500% = \frac{9.500}{100}=0.095

Mass of isotope 4 = 53.93888 amu.

% abundance of isotope 2 = 2.360% = \frac{2.360}{100}=0.0236

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=(49.94605\times 0.0435)+(51.94051 \times 0.8379)+ (52.94065\times 0.095)+(53.93888\times 0.0236)

A=51.99592amu

Therefore, the average atomic mass of the element X is 51.99592 amu

5 0
2 years ago
A chemist mixes 500 g of lead at 500°c with 1,200 g of water at 20°c. she then mixes 500 g of copper at 500°c with 1,200 g of wa
Artemon [7]
The final temperature of the lead-water system will be lower than the final temperature of the copper-water system.
8 0
2 years ago
A gram of gasoline produces 45.0kj of energy when burned. gasoline has a density of 0.77/gml . how would you calculate the amoun
babymother [125]
Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:

48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ

<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>    
5 0
2 years ago
Which of the following organisms are carnivores?
sineoko [7]

Answer:

Secondary consumers

Explanation:

Carnivores are organisms that only eat meat and that rely on others for food and energy; this means that they cannot produce food themselves.

Look at the answer choices:

- Decomposers: these are organisms that break down dead matter into material that can be used later by plants to grow; carnivores do not break down dead matter; rather, they eat meat.

- Primary consumers: these are usually herbivores; they are the second level of the energy pyramid, and they eat the organisms at the bottom level. The organisms at the bottom level are plants that make their own food. Obviously, plants are not meat, so carnivores are not primary consumers.

- Producers: these are the plants at the bottom of the energy pyramid that make their own food. Carnivores do not make their own food.

Thus, the answer is secondary consumers because this level of organisms eat the organisms at the primary consumer level.

Hope this helps!

5 0
2 years ago
A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b
Dima020 [189]
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
4 0
2 years ago
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