Answer:
option (a). The surface area and volume of a body of rotation
is the correct option
Explanation:
Theorems of Pappus and Guldinus are used to find the surface area and volume of a revolving body. It is neither applicable for surface areas and volumes of a symmetric body nor it helps to find the overall mass of any body. Thus, it can help to calculate the surface area and volume of any body rotated in 2-D frame(or any 2-D curve).
It is given or calculated as the product of area, perpendicular distance from the axis and length of the 2-D curve.
Answer:
Condition to break: ![H[j] \geq max {H[2j] , H[2j+1]}](https://tex.z-dn.net/?f=H%5Bj%5D%20%5Cgeq%20max%20%7BH%5B2j%5D%20%2C%20H%5B2j%2B1%5D%7D)
Efficiency: O(n).
Explanation:
Previous concepts
Heap algorithm is used to create all the possible permutations with K possible objects. Was created by B. R Heap in 1963.
Parental dominance condition represent a condition that is satisfied when the parent element is greater than his children.
Solution to the problem
We assume that we have an array H of size n for the algorithm.
It's important on this case analyze the parental dominance condition in order to the algorithm can work and construc a heap.
For this case we can set a counter j =1,2,... [n/2] (We just check until n/2 since in order to create a heap we need to satisfy minimum n/2 possible comparisions![and we need to check this:Break condition: [tex]H[j] \geq max {H[2j] , H[2j+1]}](https://tex.z-dn.net/?f=%20and%20we%20need%20to%20check%20this%3A%3C%2Fp%3E%3Cp%3E%3Cstrong%3EBreak%20condition%3A%20%3C%2Fstrong%3E%5Btex%5DH%5Bj%5D%20%5Cgeq%20max%20%7BH%5B2j%5D%20%2C%20H%5B2j%2B1%5D%7D)
And we just need to check on the array the last condition and if is not satisfied for any value of the counter j we need to stop the algorithm and the array would not a heap. Otherwise if we satisfy the condition for each
then we will have a heap.
On this case this algorithm needs to compare 2*(n/2) times the values and the efficiency is given by O(n).
Answer:
25 -
mm
Explanation:
Given data
steel tube : outer diameter = 50-mm
power transmitted = 100 KW
frequency(f) = 34 Hz
shearing stress ≤ 60 MPa
Determine tube thickness
firstly we calculate the ; power, angular velocity and torque of the tube
power = T(torque) * w (angular velocity)
angular velocity ( w ) = 2
f = 2 *
* 34 = 213.71
Torque (T) = power / angular velocity = 100000 / 213.71 = 467.92 N.m/s
next we calculate the inner diameter using the relation
= 467.92 / (60 * 10^6) = 7.8 * 10^-6 m^3
also
c2 = (50/2) = 25 mm
=
= ![\frac{\pi }{0.050} [ ( 0.025^{4} - c^{4} _{1} ) ]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B0.050%7D%20%5B%20%28%200.025%5E%7B4%7D%20-%20c%5E%7B4%7D%20_%7B1%7D%20%20%29%20%5D)
therefore; 0.025^4 -
= 0.050 /
(7.8 *10^-6)
= 39.06 * 10 ^-8 - ( 1.59*10^-2 * 7.8*10^-6)
39.06 * 10^-8 - 12.402 * 10^-8 =26.66 *10^-8
=
THE TUBE THICKNESS
= 25 -
mm
Answer:
option B
Explanation:
The correct answer is option B
Seaming is an operation in which the edges are folded over another part to achieve the tight fit.
Seaming is generally used to join other parts together.
So, seaming is generally used for producing fluid-tight joints.
This process is used in the food industry on canned goods, metal roofing, and in the automotive industry.