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Lina20 [59]
2 years ago
6

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

aring a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a)If a human centrifuge has a radius of 4.64 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?

____ rad/s
(b)What linear speed (in m/s) would a person in the centrifuge have at this acceleration?

____m/s
Physics
1 answer:
Alex_Xolod [135]2 years ago
5 0

a) 4.36 rad/s

b) 20.2 m/s

Explanation:

a)

For an object in uniform circular motion, the centripetal acceleration is related to the angular speed by the equation

a=\omega^2 r

where

a is the centripetal acceleration

\omega is the angular speed

r is the radius of the circle

For the person in this problem we have:

a=9g=88.2 m/s^2 is the centripetal acceleration

r = 4.64 m is the radius of the trajectory

Solving for \omega, we find the required angular speed to produce this centripetal acceleration:

\omega=\sqrt{\frac{a}{r}}=\sqrt{\frac{88.2}{4.64}}=4.36 rad/s

b)

For a uniform circular motion, the relationship between angular speed and linear speed is

v=\omega r

where

v is the linear  speed

\omega is the angular speed

r is the radius of the circle

For the person in this problem we have:

\omega=4.36 rad/s is the angular speed

r = 4.64 m is the radius of the circle

Therefore, the linear speed is:

v=(4.36)(4.64)=20.2 m/s

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A heat engine (Power Cycle) with a thermal efficiency of 35 percent efficiency produces 750 kJ of work. Heat transfer to the eng
frosja888 [35]

Answer:

a) The schematic illustrating is attached

b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ

c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ

Explanation:

b) The heat transfer to the engine and the heat transfer from the engine to the air is:

Q_{1} =\frac{W}{n}

Where

W = 750 kJ

n = 35% = 0.25

Replacing:

Q_{1} =\frac{750}{0.35} =2142.86kJ

Q_{2} =Q_{1} -W=2142.86-750=1392.86kJ

c) The efficiency of Carnot engine is:

n=1-\frac{300K}{550K} =0.455

The heat transfer to the heat engine is:

Q_{1c} =\frac{750}{0.455} =1648.35kJ

The heat transfer from the heat engine is:

Q_{2c} =1648.35-750=898.35kJ

4 0
2 years ago
Two cables of the same length are made of the same material, except that one cable has twice the diameter of the other cable. Wh
belka [17]

Answer: The same current flows through bth cables

Explanation:

Lets have a look to the next two equations

The Ohm´s     V = I*R    (1)

where:

V is voltage (potencial dfference) in volts

I is the electric current in ampers

R is the electric resistance

When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same

And in the other hand the resistance  R =ρL/s

Where  ρ is the resistivity of the conductor  L the length and s square section of the conductor

If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)

Tables exist where to find the capacity of each cable according to its diameter.

6 0
2 years ago
Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.
tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

s=ut+\frac{1}{2}*gt^{2}  \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0
2 years ago
Which statements describe the applications of nuclear medicine scans? Check all that apply.
coldgirl [10]

Answer:

- asses disease progression and tissue function

- utilize a biologically active molecule

- utilize a radionuclide tracer

Explanation:

4 0
2 years ago
Read 2 more answers
A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial
puteri [66]

Answer:

A) vertically upward

Explanation:

Since the tyre is rotating with uniform angular speed and moving with constant linear speed

So as soon as a small stone is stuck into the groove of the tyre the speed of the stone is same as that of the tyre

so now we can say that stone will start revolving with the tyre of the car at constant angular speed and moving with uniform speed also

so here just after that the tangential acceleration of the stone must be zero while radial acceleration must be towards the center of the tyre given as

a_c = \omega^2 R

so we will have direction of net acceleration is towards its center so correct answer will be

A) vertically upward

7 0
2 years ago
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