<span>It rises confidence for the reason that the more times you conduct the similar experiment over and over should either demonstrate your hypothesis right and wrong and remove any random incidences that might touch your results. Meaning it permits to have a more accurate measure or conclusion.</span>
Answer:
C)We cannot be sure unless we find out its boiling point.
Explanation:
It is necessary to clearly explain here that simply observing two compounds of the same homologous series irrespective of how close they may be in the series will not give us the faintest idea regarding which one will be a liquid, solid or gas at room temperature.
However, to determine whether an unknown substance will be a liquid at room temperature, then its important to measure its boiling point. If the boiling point is above room temperature, and the melting point is below room temperature, the compound is a liquid. If the boiling point of the unknown substance is below room temperature, it is a gas.
It is now safe to conclude that cannot decide on the state of matter in which a compound exists unless we know something about its boiling point, not merely looking closely at the properties of its neighbouring compounds in the same homologous series
<span>Carbon Monoxide.
First, determine the relative number of moles of each element by looking up the atomic weights of carbon and oxygen
Atomic weight carbon = 12.0107
Atomic weight oxygen = 15.999
Moles of Carbon = 24.50 g / 12.0107 g/mol = 2.039847802 mol
Moles of Oxygen = 32.59 g / 15.999 g/mol = 2.037002313 mol
Given that the number of moles of both carbon and oxygen are nearly identical, it wouldn't be unreasonable to think that the empirical formula for the compound is CO which also happens to be the formula for Carbon Monoxide.</span>
The balance chemical equation is:
NaCH₃COO + HCl → NaCl + HCH₃COO
Make
M=D*V
D=620 g/cm³
V=75 cm³
m= 620 g/cm³ * 75 cm³=46500 g
m=46500g
