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GenaCL600 [577]
2 years ago
14

The total pressure for a mixture of N2O4 and NO2 is 1.5atm. If Kp = 7.1 at 25°C, calculate the partial pressure of each gas in t

he mixture. (HINT 1.5 = 2pNO2 + pN2O4) 2NO2 (g) = N2O4 (g)
Chemistry
1 answer:
kondor19780726 [428]2 years ago
6 0

Answer:

N_{2} O_{4} : 0.5 atm and N_{} O_{2} : 1 atm

Explanation:

In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.

It is given that P_{total} = 1.5 atm

The mole fraction of each gas can be calculated in the following way:

N_{2} O_{4} = moles of N_{2} O_{4} ÷ total moles present = \frac{1}{3}

N_{} O_{2} = moles of N_{} O_{2} ÷ total moles present = \frac{2}{3}

Partial pressure of N_{2} O_{4} : 1.5 × \frac{1}{3} = 0.5 atm

Partial pressure of N_{} O_{2} : 1.5 × \frac{2}{3} = 1 atm

Hope that answers the question, have a great day!

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Molarity is defined as number of moles of solute in 1 L of solution.

Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.

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From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:

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Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:

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Explanation:

The water of a rock pool lined with mineral crystals is a <em>saturated solution</em> of said mineral, this means the concentration of X in those 36 mL is the solubility of compound X in water at 17 °C.

  • This means<u> it is possible to calculate said solubility</u>.

The dilution of the sample is not relevant, nor is that 500 mL volume. What's important is that 3.96 g of X form a saturated solution with 36.0 mL of water, so the solubility is:

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