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sergejj [24]
2 years ago
7

A certain weightlifter is prone to back injury. He finds that he has a 20% chance of hurting his back if he uses the proper form

of bending at the hips and keeping his spine locked. The probability that he will hurt his back with bad form is 95%. The probability that he uses proper form is 75%. What is the probability he hurts his back
Mathematics
1 answer:
drek231 [11]2 years ago
4 0

Answer:

Probability weightlifter hurts his back = 0.3875 i.e 38.75%

Step-by-step explanation:

Probability of using right body form = 75%

Probability of using bad body form : 1 - Prob (right body form) = 1 - 75% = 25%  

Probability of getting injured if right body form = 20%

Probability of getting injured if using bad body form = 95%

  • Probability of getting injury :

Prob (Right body form & injury) or Prob (wrong body firm & injury)

(0.75) (0.20) + (0.25) (0.95)

0.15 + 0.2375

= 0.3875 i.e 38.75%

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2 years ago
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Step-by-step explanation:

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A student raises her grade average from a 75 to a 90. What was the percent of increase
son4ous [18]
This can be solved algebraically. Before we start, as context, to find a percentage you multiply by the percentage/100.

75*x=90 \\ x= \frac{90}{75}  \\  \\ \boxed{x=1.2}

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2 years ago
Peyton plans to deposit her next paycheck into her savings account.she makes $12.50 per hour and her next paycheck will be h hou
Snowcat [4.5K]

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5 0
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One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north
tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, \bar x = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have t_{\alpha /2} = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0
2 years ago
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