Printer A
y = 14x
Printer B
Time(min) | 3 | 5 | 8 | 12 |
Pages printed | 48 | 80 | 128 | 192 |
Printer A prints 14(1) = 14 pages per minute.
Printer B prints 48/3 = 16 pages per minute.
The printer that prints at a faster rate is printer B.
Answer is C
14.2+6.5(p+3q)-4.05q
14.2+6.5p+19.5q-4.05q
14.2+6.5p+15.45q→6.5p+15.45q+14.2
so the answer is C
Answer:
53 teachers
Step-by-step explanation:
Basically, what we need to do here is to find how many teachers there need to be, first. If there are 6,734 students in the school district and if maximum class size is 25, then the number of teachers needed is:
6,734 / 25 = 269.36
Of course, it's obvious that we can't have a decimal number of teachers, so we need to find integer (269 or 270).
If we take 269 teachers and 25 students per class, we get:
269 • 25 = 6,725 students, which is not enough, since there are 6,734 students.
That means that the number of teachers needed is 270.
It is given that there are already 217 teachers, meaning that 270-217=53 teachers have to be supplemented.
Answer:
it means the the line falls on 9 on the x-axis
and intersects at 378 on the y-axis
Step-by-step explanation:
hope that helped
Answer:
0.245489 cubic meters.
Step-by-step explanation:
It is given that a firkin is an old British unit of volume equal to 9 gallons.
1 firkin = 9 gallons
6 firkins = 54 gallons
We need convert 6.00 firkins to cubic meters.
We know that,
1 gallon = 0.00454609 cubic meters
54 gallon = 0.24548886 cubic meters
6 firkins = 0.245489 cubic meters.
Therefore, 6.00 firkins is equivalent to 0.245489 cubic meters.
