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Masteriza [31]
2 years ago
7

Write a function called st_dev. St_dev should have one #parameter, a filename. The file will contain one integer on #each line.

The function should return the population standard #deviation of those numbers.
Computers and Technology
1 answer:
kodGreya [7K]2 years ago
6 0

Answer:

  1. import statistics
  2. def st_dev(file_name):
  3.    with open(file_name) as file:
  4.        data = file.readlines()
  5.        numList = []
  6.        for x in data:
  7.            numList.append(int(x))
  8.        
  9.        return statistics.pstdev(numList)
  10. print(st_dev("text1.txt"))

Explanation:

The solution code is written using Python.

To ease the calculation task, we can import Python statistics module to use the pstdev method to calculate the population standard deviation of a list of numbers (Line 1).

Next, create a st_dev function that take single argument file_name (Line 3). In the function, it will open the input file and read the data line by line (Line 4-5). Create a for loop to traverse through each line of the data which is an integer and append it to numList (Line 7-8). We can pass the numList to pstdev method (Line 10) and return the resulting standard deviation value as output.

We test the function by passing a file which hold a list of integer values in each line (Line 12).

8

9

12

11

21

15

16

10

7

13

And the output we shall get is 4.019950248448356

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Elza [17]

Answer:

Explanation:

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5 0
2 years ago
Write a flowchart and C code for a program that does the following: Within main(), it asks for the user's annual income. Within
Fiesta28 [93]

Answer:

I am writing a C program:

#include <stdio.h> //to use input output functions

void printIt(double annual_in){ //function printIt

   if(annual_in >90000) //check if the income is greater than 90000

   printf("Congratulations. Doing great!"); //print this message if income value is greater than 90000

   else //if annual income is less than 90000

   printf("You WILL make $50,000, if you keep going"); } //print this message if income value is less than 90000

int main() //start of main() funciton body  

{   double income; //declares a double type variable income to hold annual income value

   printf("Enter annual income: "); //prompts user to enter annual income

   scanf("%lf",&income); //reads income value from user

   printIt(income); } // calls printIt method by passing input income to that function

     

Explanation:

The program is well explained in the comments mentioned with each statement of the program. The flowchart is attached.

First flowchart flow1 has a separate main program flowchart which reads the income and calls printIt function. A second flowchart is of prinIt() method that checks the input income passed by main function and displays the corresponding messages and return.

The second flowchart flow2 is the simple flowchart that simply gives functional description of the C program as flowchart is not where giving function definitions is important. Instead of defining the function printIt separately for this C program, a high-level representation of functional aspects of this program is described in second flowchart while not getting into implementation details.

7 0
2 years ago
Considering the following algorithm, which of the following requirements are satisfied?
Alisiya [41]

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

bool thread1Access = true;

bool thread2Access = true;

thread1 { thread2 {

While (true) {

                   While (true)

                                   {

                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

                                              If (currentThread == 1)

                                                {        

                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

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2 years ago
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