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vesna_86 [32]
2 years ago
14

The box of negligible size is sliding down along a curved path defined by the parabola y=0.4x2. When it is a A(xA = 2 m, yA = 1.

6 m), the speed is v = 8 m/s and the increase in speed is dv/dt = 4 m/s2
Physics
2 answers:
Leokris [45]2 years ago
5 0

Answer:

a=8.06m/s^2

Explanation:

The box can be considered negligible body slidding down along  a curved path defined by the parabola Y=Ax^2

Note:

When it's at A(x=2m, y=1.6m),

the speed Vb=8m/s and the increase in speed=4m/s^2

To find the acceleration,

Y=Ax^2

dy/dx=8x

d^2y/dx^2=8

p={[1+(dy/dx)^2]^3/2}/|d^2y/dx^2| .......1

substituting into 1, we have

p=8.39624m

an=v^2/p

an=8^2/8.39624=7.6224m/s^2

a=sqrt(at^2+an^2)

a=sqrt(4^2+7.62246^2)

a=8.06m/s^2

Nat2105 [25]2 years ago
5 0

Answer:

acceleration = 8²/8.4 = 7.62m/s².

Explanation:

Given that at A

x = 2m, y = 1.6m

y = 0.4x²

dy/dx = 0.8x

At x = 2m

This acceleration is that of a body around a circular path of radius of curvature r. Since the position is given by a function y(x). We will use calculus to get the radius and then find the acceleration a = v²/r

The radius of curvature of the path from calculus is given by

r=([1+(dy/dx)²]^(3/2))/(d²y/dx²)

dy/dx = 0.8×2 = 1.6

d²y/dx² = 0.8

r = ([1+(1.6)²]^(3/2))/(0.8) = ([1+ 2.56]^1.5)/0.8 = 3.56^1.5/0.8 = 6.72/0.8 = 8.4m

r = 8.4m

acceleration = v²/r

At this instant v = 8m/s

acceleration = 8²/8.4 = 7.62m/s².

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2 years ago
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7. A local sign company needs to install a new billboard. The signpost is 30 m tall, and the ladder truck is parked 24 m away fr
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<h2>Solution :</h2>

Here ,

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Answer:

<u></u>

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Even though the syntax of the text is not completely clear, likely because it accompanies a drawing that is not included, it results clear that the posittion A is where the seat is at the lowest position, and the position B is upper.

The gravitational <em>potential energy </em>is directly proportional to the height of the objects with respect to some reference altitude. Thus, when the seat is at the position A the swing has the smallest potential energy and when the seat is at the <em>position B the swing has the greatest potential energy.</em>

Regarding the forms of energy, as the swing moves from point B to point A, it is going downward, gaining kinetic energy (speed) at the expense of the potential energy (losing altitude). When the seat passes by the position A, the kinetic energy is maximum and the potential energy is miminum. Then the seat starts to gain altitude again, losing the kinetic energy and gaining potential energy, up to it gets to the other end,

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11111nata11111 [884]

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