Bob Bluster, the KNEWS meteorologist, determined that the mathematical odds of $\emph{no rain}$ tomorrow are 11:9. What would a
1 answer:
Answer:
45% chance there will be rain tomorrow.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
11:9 odds that there will be no rain
In 11+9 = 20 experiments, in 11 there will be no rain and 9 there will be rain.
Percent change there is rain:
Desired outcomes:
9 experiments(rain)
Total outcomes:
20 experiments
Probability
45% chance there will be rain tomorrow.
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Answer:
1. The Venn diagrams are attached
2. When the statistics students number = 10·x + 3, we have;
The number of students that study
a. Algebra = 128/11
b. Statistic = 213/11
When the statistics students number = 2·x + 3, we have;
The number of students that study
a. Algebra = 16
b. Statistic = 15
Step-by-step explanation:
The parameters given are;
Total number of students = 30
Number of students that study algebra n(A) = x + 10
Number of students that study statistics n(B) = 10·x + 3
Number of student that study both algebra and statistics n(A∩B) = 4
Number of student that study only algebra n(A\B) = 2·x
Number of students that study neither algebra or statistics n(A∪B)' = 3
Therefore;
The number of students that study either algebra or statistics = n(A∪B)
From set theory we have;
n(A∪B) = n(A) + n(B) - n(A∩B)
n(A∪B) = 30 - 3 = 27
Therefore, we have;
n(A∪B) = x + 10 + 10·x + 3 - 4 = 27
11·x+13 = 27 + 4 = 31
11·x = 18
x = 18/11
The number of students that study
a. Algebra
n(A) = 18/11 + 10 = 128/11
b. Statistic
n(B) = 213/11
Hence, we have;
n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11
Similarly, we have;
n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11
However, assuming n(B) = (2·x + 3), we have;
n(A∪B) = n(A) + n(B) - n(A∩B)
n(A∪B) = 30 - 3 = 27
Therefore, we have;
n(A∪B) = x + 10 + 2·x + 3 - 4 = 27
2·x+3 + x + 10= 27 + 4 = 31
3·x = 18
x = 6
Therefore, the number of students that study
a. Algebra
n(A) = 16
b. Statistics
n(B) = 15
Hence, we have;
n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12
Similarly, we have;
n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11
The Venn diagrams can be presented as follows;
Answer:
46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups
Step-by-step explanation:
We use two binomial trials to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Probability of at least nine participants finishing the study in a group.
0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that .
10 students, so
We have to find:
Then
0.3758 probability that at least nine participants complete the study in a group.
Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?
0.3758 probability that at least nine participants complete the study in a group. This means that
Two groups, so
We have to find P(X = 1).
46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups
Answer:
The last two terms of the expression are
Both the last terms has variable of degree equal to (2+4=6) and (3+3=6).So, the first term must have degree greater than 6.
Correct Options are