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blagie [28]
2 years ago
15

How many grams of butane can be burned by 1.42 moles of oxygen?

Chemistry
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

So the molar mass of C4,H10 is

58.12g mole -1

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Keith_Richards [23]

It bonds atoms together to create molecules

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2 years ago
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A reaction produces a gas, which is collected in a glass cylinder. When a glowing splint is placed inside the container, it burn
Gnesinka [82]

Answer:

true

Explanation:

5 0
2 years ago
What is the mass of 2.11 × 1024 sulfur atoms??
Kryger [21]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:

2.11x 10^24 atoms ( 1 mol / 6.022x10^23 atoms ) ( 32.06 g / 1 mol ) = 112.33 g sulfur

Hope this answers the question. </span>
8 0
2 years ago
Which of the following compounds has the highest pKa value? A)CCl3CH2NH2
Rudik [331]
The lower the pKa<span> of a Bronsted acid, the more easily it gives up its proton. The </span>higher<span> the </span>pKa<span> of a Bronsted acid, the more tightly the proton is held, and the less easily the proton is given up.

Here we need the highest pKa, so we need to see which compound  will less likely to give proton or hydrogen ion.

</span><span>Now, all Nitrogen contains a lone pair. But HALOGEN groups( F, Cl, only) being electronegative than NITROGEN [electronegativity of N=3, F=4 and Cl=3], pulls electron pair towards itself. 
</span>
The more the lone pair of nitrogen is pulled, the more strong bond between N and H will become, which means less likely to give hydrogen ion.
means high Pka

C) option is the answer because it has 3 F very close to N.
3 0
2 years ago
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
Read 2 more answers
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