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White raven [17]
2 years ago
11

Weak acids are usually one of the following: 1. hydrofluoric acid, ____________ , 2. acids in which the proton is not bonded to

an oxygen atom or a halogen (ex. ____________ ), 3. ____________ where the number of oxygen atoms equals or only exceeds by ____________ the number of ionizable ____________ (ex. ____________ ) or 4. ____________ (ex. ____________ ).
Chemistry
1 answer:
oee [108]2 years ago
6 0

Answer: 1).  Weak acids are usually one of the following: 1. hydrofluoric acid, CH_{3}COOH.

2). Acids in which the proton is not bonded to an oxygen atom or a halogen (ex. HCN ).

3). Oxo-acids where the number of oxygen atoms equals or only exceeds by 1 the number of ionizable protons (ex.HNO_{3}) or

4). Carboxylic acids (ex. CH_{3}COOH).

Explanation:

Weak acids are the species which partially dissociate into ions when added to water. For example, acetic acid (CH_{3}COOH) is a weak acid.

Acids in which the proton is not bonded to an oxygen atom or a halogen is HCN.

Oxo-acids are the acids which contain oxygen atom. For example, HNO_{3}, H_{2}SO_{4}, R-COOh etc are all oxo-acids.

In oxo-acids, the number of oxygen atoms equals or only exceeds by 1 the number of ionizable protons.

Thus, we can conclude that:

1).  Weak acids are usually one of the following: 1. hydrofluoric acid, CH_{3}COOH.

2). Acids in which the proton is not bonded to an oxygen atom or a halogen (ex. HCN ).

3). Oxo-acids where the number of oxygen atoms equals or only exceeds by 1 the number of ionizable protons (ex.HNO_{3}) or 4. Carboxylic acids (ex. CH_{3}COOH).

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. A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture
postnew [5]

Answer:

A) Mass flow rate of air = 22.892 kmol/hr

B)percentage by mass of oxygen in the product gas = 22.52%

Explanation:

We are given that the mixture containing 9.0 mole% methane in air flowing.

Thus, we have 0.09 mole of methane(CH4) and the remaining will be the air which is (100% - 9%) = 91% = 0.91

Molar mass of CH4 = 12 + 1(4) = 16 g/mol

We are given the average molecular weight of air = 29 g/mol

Thus;

Average molar mass of air and methane mixture is;

M_avg = (0.09 × 16) + (0.91 × 29)

M_avg = 27.83 g/mol

We are told that air flowing at a rate of 7 × 10² kg/h = 700 kg/h

Thus;

Mass flow rate of CH4 in air mixture = 700kg/h × (0.09CH4)/1 mix × (1/27.83kg/kmol) = 2.264 kmol/hr

Mass flow rate of air in mixture = 2.264kmol/h × 0.91kmol air/0.09kmolCH4 = 22.892 kmol/hr

We are told that the mixture is capable of being ignited if the mole percent of methane is between 5% and 15%.

Thus, for 5% of methane, the air required will be;

2.264kmol/h × 0.95kmol air/0.05kmol CH4 = 43.016 kmol/hr

Now, the dilution air needed will be =

43.016 - 22.892 = 20.124 kmol/hr

Total mass flow rate of mixture =

700kg/hr + (20.124kmol/hr × 29kg/mol) = 1283.596 kg/hr

We are told that air consist of 21 mole% Oxygen (O2).

Molar mass of oxygen = 32

Thus;

Mass fraction of oxygen in the product gas = 43.016kmol/h × (0.21molO2/1mol air) × (32kg oxygen/1kmol oxygen) × (1/1283.596kg/h) = 0.2252

Thus, written in percentage form, we have; 22.52%

So, percentage by mass of oxygen in the product gas = 22.52%

3 0
2 years ago
One molecule of a compound weighs 2.03x10-22 g. what is the molar mass of that compound?
stealth61 [152]
<span>The molar mass of the compound is 122 g. </span>
6 0
2 years ago
Read 2 more answers
The noble gases are inert. This means they a. exist as gases at room temperature. b. undergo many chemical reactions. c. lose an
eduard

Answer:

D

Explanation:

The noble gases are said to be inert because they undergo very few chemical reactions. They enjoy their status by having completely filled electron shells and do not have any reason whatsoever to go into chemical reactions. Most elements otherwise go into chemical reactions principally to enjoy the stability of these elements.

Noble gases can be found in the last group of the periodic table.

8 0
2 years ago
You are eating a pizza. What type of mixture are you consuming?
Hitman42 [59]

Answer:

Explanation:

Cheese, Meat, dough, Sauce

3 0
2 years ago
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The volume of a gas is 36.0 ml at 10.0°c and 4.50 atm. at what temperature (°c) will the gas have a pressure of 3.50 atm and a v
galben [10]
Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
5 0
2 years ago
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