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Kryger [21]
2 years ago
5

The primary factor in decreasing the Kinetic Energy of an object is to:

Mathematics
1 answer:
nordsb [41]2 years ago
7 0

Answer:

Decrease Mass, rather then velocity because the heavier it is the faster it will be

You might be interested in
What is the place value of 3 in 9. 365?​
nikdorinn [45]

Answer:

It is in the tenths place

Step-by-step explanation:

In the number 9.365, 3 is in the tenths place.

8 0
2 years ago
Read 2 more answers
A basic cellular package costs $20 per month for 60 minutes of calling, with an additional charge of $0.20/min beyond that time.
Anika [276]

Answer: you can use 260 min, 60 min at a fixed price ($20) and extra 200.

Step-by-step explanation:

C(x) = 20 + 0.20(x − 60)

C(x) ≤ 60

20 + 0.20(x − 60) ≤ 60

0.20(x − 60) ≤ 60 - 20

0.20x - 12 ≤ 40

0.20x ≤ 40 + 12

0.20x ≤ 52

x ≤ 52/0.2

x ≤ 260

This way, you can use 260 min, 60 min at a fixed price ($20) and extra 200.

7 0
2 years ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
Mr. Smith had 33 dozen cans. He sold 340 of them at 15$ each. He sold the remaining cans at a discount of 20% each. How much mon
iren2701 [21]

Answer:

Mr. Smith collects $5748 from selling the can.

Step-by-step explanation:

Given total number of cans = 33\times12=396

Selling price of one can = $15.

\therefore \textrm{Selling price of 340 cans} = \textrm {selling price of one can} \times \textrm {number of cans}=15\times340=\$5100

Now remaining number of cans = total number of cans - sold number of cans =396-340=54

For remaining number of cans he gives a discount of 20% each,

∴ Selling price of one can = 15-\frac{15\times20}{100}=15-3=12

∴ Selling price of 54 cans = \textrm{selling price of one can} \times \textrm{number of cans}=12\times54=\$648

So total money he earns =  \$5100+\$648= \$5748.

Thus Mr. Smith earns $5748 by selling the cans.

3 0
2 years ago
The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students re
Vladimir79 [104]

Answer:

The 95% of confidence intervals

(2.84 ,2.99)

Step-by-step explanation:

A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16

given small sample size n =20

sample mean x⁻ =2.92

sample standard deviation 'S' =0.16

level of significance ∝ =  0.95

The 95% of confidence intervals

x^{-}  ± t_{\alpha } \frac{S}{\sqrt{n} }

the degrees of freedom γ=n-1 =20-1=19

t-table 2.093

(x^{-}  - t_{\alpha } \frac{S}{\sqrt{n} },x^{-}  + t_{\alpha } \frac{S}{\sqrt{n} })

(2.92 - 2.093(\frac{0.16}{\sqrt{20} } ,2.92+2.093(\frac{0.16}{\sqrt{20} } )

(2.92-0.0748,2.92+0.0748)

(2.84 ,2.99)

Therefore the 95% of confidence intervals

(2.84 ,2.99)

4 0
2 years ago
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