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Genrish500 [490]
2 years ago
6

Consider an acrylic sheet of thickness L = 5 mm that is used to coat a hot, isothermal metal substrate at Th = 300°C. The proper

ties of the acrylic are rho = 1990 kg/m3, c = 1470 J/kg · K, and k = 0.21 W/m · K. Neglecting the thermal contact resistance between the acrylic and the metal substrate, determine how long it will take for the insulated back side of the acrylic to reach its softening temperature, Tsoft = 90°C. The initial acrylic temperature is Ti = 20°C.

Physics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

74.52s

Explanation:

The solution is shown in the picture below

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Two speakers face each other, and they each emit a sound of wavelength λ. One speaker is 180∘ out of phase with respect to the o
mel-nik [20]

Answer:

a. 3/4λ

d. 1/4λ

Explanation:

When the wavelength of the sound waves is λ and the two waves are having same frequency the waves are said to be out of phase if their phase difference is in the multiples of \frac{\lambda}{2} or 180°.

When the two waves are out of phase then their opposite maxima coincide at the same time resulting in the minimum amplitude of the resulting wave throughout.

  • As we observe from the schematic that the a wave has sinusoidal pattern of variation and we get a maxima after each \frac{\lambda}{4} of the distance.
  • Here we have two speakers out of phase therefore on shifting one of the speakers by the odd multiples of \frac{\lambda}{2} we have the maxima or the extreme amplitudes.

So, we must place the microphone at  3/4λ and 1/4λ to pickup the loudest sound.

4 0
2 years ago
A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational
a_sh-v [17]

Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: F = 49.06N

Pebble: F = 29.44N

(b)Calculate the magnitude of the acceleration of each object when released.

Rock: a =9.8m/s^{2}

Pebble:  a =9.8m/s^{2}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{m1m2}{r^{2}}  (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

<em>Case for the rock </em>m = 5.0 Kg<em>:</em>

m1 will be equal to the mass of the Earth m1 = 5.972×10^{24} Kg and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth r = 6371000m.

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(5.0 Kg)}{(6371000 m)^{2}}

F = 49.06N

Newton's second law can be used to know the acceleration.

F = ma

a =\frac{F}{m} (2)

a =\frac{(49.06 Kg.m/s^{2})}{(5.0 Kg)}

a =9.8m/s^{2}

<em>Case for the pebble </em>m = 3.0 Kg<em>:</em>

F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(3.0 Kg)}{(6371000 m)^{2}}

F = 29.44N

a =\frac{F}{m}

a =\frac{(29.44 Kg.m/s^{2})}{(3.0 Kg)}

a =9.8m/s^{2}

3 0
2 years ago
Read 2 more answers
Compare the components that make up the windsurfer, his board, and his surroundings.
frozen [14]

Answer:

Sample Response: The windsurfer, his board, and the air and water around him are all made of matter. That matter is made up of very small particles called atoms.

Explanation:

i just finished lesson on edgenuity :)

7 0
2 years ago
Read 2 more answers
At time t, gives the position of a 3.0 kg particle relative to the origin of an xy coordinate system ( ModifyingAbove r With rig
Elena-2011 [213]

Complete Question

  The complete Question is shown on the first uploaded image

Answer:

a

The torque acting on the particle is  \tau = 48t \r k

b

The magnitude of the angular momentum increases relative to the origin

Explanation:

From the equation we are told that

      The position of the particle is   \= r = 4.0 t^2 \r i - (2.0 t - 6.0 t^2 ) \r j

       The mass of the particle is m = 3.0 kg

        The time is  t

   

The torque acting on  the particle is mathematically represented as

           \tau = \frac{ d \r l }{dt}

where \r l is change in angular momentum which is mathematically represented as

       \r l = m (\r r \ \ X  \ \ \r v)

Where X mean cross- product

   \r v is the velocity which is mathematically represented as

           \r v = \frac{d \r r }{dt}

Substituting for  \r r

           \r v = \frac{d }{dt} [ 4 t^2 \r i - (2t + 6t^2 ) \r j]

           \r v =  8t \r i - (2 + 12 t) \r j

Now the cross product of \r r \ and \ \r v is  mathematically evaluated as    

          \r r  \  \ X \ \ \r v = \left[\begin{array}{ccc}{\r i}&{\r j}&{\r k}\\{4t^2}&{-2t -6t^2}&0\\{8t}&{-2 -12t}&0\end{array}\right]

                       = 0 \r i + 0 \r j + (- 8t^2 -48t^3 + 16t^2 + 48t^3 ) \r k

                      \r r \ \  X \ \ \r v = 8t^2 \r k

So the angular momentum becomes

       \r l = m (8t^2 \r k)

Substituting for m

      \r l = 3 *  (8t^2 \r k)

      \r l =24t^2  \r k

Substituting into equation for torque

       \tau = \frac{d}{dt} [24t^2 \r k]

       \tau = 48t \r k

The magnitude of the angular momentum can be evaluated mathematically as

        |\r l| = \sqrt{(24 t^2) ^2}

        |\r l| = 24 t^2

From the is equation we see that the magnitude of the angular momentum is varies directly with square of the time so it would relative to the origin because at the origin t= 0s and we move out from origin t increases hence angular momentum increases also

4 0
2 years ago
Is it possible for two pieces of the same metal to have different recrystallization temperatures? Is it possible for recrystalli
Butoxors [25]

Answer:

Explained

Explanation:

Two pieces of the same metal can have different recrystallization temperatures if the pieces  have been cold worked to different amounts. The piece of work cold worked to greater extend will have more internal energy to drive the recrystalline process and lower recrystallization temperature.

Yes, its possible that recrystallization to take place in some regions of a part before it does in other regions of the same part if the work has been unevenly strained or if the part have different thickness at different sections.

6 0
2 years ago
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