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Rina8888 [55]
2 years ago
6

What is the domain of the function y = StartRoot x EndRoot + 4?

Mathematics
2 answers:
Alenkinab [10]2 years ago
7 0

Answer:

3rd one

Step-by-step explanation:

FromTheMoon [43]2 years ago
4 0

Answer:

The domain of the function is 0 less-than-or-equal-to x less-than infinity ⇒ 3rd answer

Step-by-step explanation:

The domain of the function f(x) = y is all the values of x which make the function defined

∵ y=\sqrt{x}+4

- There is no square root for negative number, that means x

    must be non-negative number

∵ The non negative numbers start from zero till infinity

∴ 0 ≤ x < ∞

∴ x must be greater than or equal zero and less than infinity

- Values of x are the domain of the function

∴ The domain of the function is 0 ≤ x < ∞

The domain of the function is 0 less-than-or-equal-to x less-than infinity

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John took all his money from his savings account. He spent ​$110 on a radio and 4/11 of what was left on presents for his friend
svp [43]

Answer:

$1210

Step-by-step explanation:

Let x be total amount

First John spent $110 on a radio and 4/11 of what was left on presents for his friends so he was left with

\frac{7}{11}(x-110)=\frac{7}{11}x-70

Then he put 2/5 of his remaining money into a checking account

\frac{3}{5}\left(\frac{7}{11}x-70\right)

Rest he donated to charity

420=\frac{3}{5}\left(\frac{7}{11}x-70\right)\\\Rightarrow \left(\frac{7}{11}x-70\right)=\frac{2100}{3}\\\Rightarrow \frac{7}{11}x-70=700\\\Rightarrow \frac{7}{11}x=770\\\Rightarrow x=1210

Hence total amount of money John originally had was $1210

8 0
1 year ago
A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re
Daniel [21]

From the equation of motion, we know,

s=ut+\frac{1}{2}at^{2}

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.  

A = -9.8m/s^{2} since the ball is thrown upwards.

Plug the known values into the equation.

=> 0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = \frac{3.4}{2} = 1.7 sec

v^{2}=u^{2}+2as

=> 0=(16.67)^{2}+2(-9.81)(s)

Solving for s we get

s= 14.16 m


4 0
2 years ago
Find the difference. Express your answer in
Leokris [45]

Answer:

-4g-3

------------

g+2

Step-by-step explanation:

g+1                     5g+4

-------------  -   ------------------

g+2                     g+2

Since the denominators are the same, subtract the numerators

g+1 - (5g+4)

Distribute the negative sign

g+1 -5g-4

-4g-3

Put this back over the denominator

-4g-3

------------

g+2

6 0
2 years ago
Read 2 more answers
Round 720,051,852 to the nearest hundred
marysya [2.9K]

Answer:

720,051,900

Step-by-step explanation:

it rounds up to 720,051,900 because 5 tells you to round up

4 0
1 year ago
The proof that ΔMNS ≅ ΔQNS is shown. Given: ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. Prove: ΔMNS ≅
klio [65]
The answer is "MS and QS". Trust me I just took the test and made a 90
8 0
2 years ago
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