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Mandarinka [93]
2 years ago
3

A saline solution used in intravenous drips for patients who cannot take oral fluids contains 0.92% NaCl in water. What volume o

f the saline solution must be administered to the patient in order to deliver 7.7g of NaCl?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
3 0

Answer:

840 mL  

Explanation:

I assume the solution is 0.92 % (w/v) NaCl in water.  

\text{Volume} = \text{7.7 g NaCl} \times \dfrac{\text{100 mL solution}}{\text{0.92 g NaCl}} = \textbf{840 mL}

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How many grams of KBr are required to make 550. mL of a 0.115 M KBr solution?
In-s [12.5K]

Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. We calculate as follows:

0.115 M = n mol KBr / .55 L solution

n = 0.06325 mol KBr

mass = 0.06325 mol KBr (119 g / mol) = 7.53 g KBr

4 0
2 years ago
Select the correct answer. A student places a sample of white sodium bicarbonate powder in a test tube and heats it. The student
inessss [21]

Answer is: D. It is not sodium bicarbonate.

Balanced chemical reaction of heating sodium bicarbonate:                    2NaHCO₃ → Na₂CO₃ + CO₂ + H₂O.

This is chemical change (chemical reaction), because new substances are formed (sodium carbonate, carbon(IV) oxide and water), the atoms are rearranged, so there is no sodium bicarbonate (NaHCO₃) in the test tube.

8 0
2 years ago
The volume of a single strontium atom is 4.15×10-23 cm3. What is the volume of a strontium atom in microliters
Ivenika [448]

Answer:-  4.15*10^-^2^0\mu L

Solution:- It is a volume unit conversion problem where we are asked to convert the volume from cm^3 to microliters.

We know that:

1cm^3 = 1 mL

1mL=10^-^3L

and, 1L=10^6\mu L

Let's use these conversions factors for the desired conversion using dimensional as:

4.15*10^-^2^3cm^3(\frac{1mL}{1cm^3})(\frac{10^-^3L}{1mL})(\frac{10^6\mu L}{1L})

= 4.15*10^-^2^0\mu L

So, the answer is  4.15*10^-^2^0\mu L .

7 0
2 years ago
What element is used in bright flashing advertising signs
Sergeu [11.5K]
The element used in advertising signs is neon.
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2 years ago
Lithium chloride forms three hydrates. They are LiCl.H2O, LiCl.2H2O and LiCl.3H2O.
Stels [109]

Answer:

The answer is LiCl.2H2O

Explanation:

Li=7

Cl=35.5

O=16

LiCl.H2O

7+35.5+16+2

60.5

%comp=60.5/78.5×100

22.9

LiCl.2H20

7+35.5+2(2+16)

42.5+36

78.5

%comp=36/78.5×100

45.9

LiCl.3H20

7+35.5+3(2+16)

42.5+54

96.5

54/96.5×100

56.0

7 0
2 years ago
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