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3241004551 [841]

2 years ago

4

Sylvia and Jadon now want to work a problem. Imagine a puck of mass 0.5 kg moving as in the simulation. Suppose that the tension

in the string is 3.0 N, and that the radius of its circular path is 0.6 m. What will Jadon and Sylvia find for the tangential speed of the puck?

1 answer:

Sidana [21]2 years ago

7 0

Answer:

1.897 m/s

Explanation:

The tension T = 3N of the string is caused by the centripetal acceleration of the puck, which can be calculated as the following using Newton's 2nd law:

$a_c = T / m = 3 / 0.5 = 6 m/s^2$

From the centripetal acceleration, the tangential speed of the puck can be calculated using the following formula

$a_c = v^2/r$

$v^2 = a_c r = 6*0.6 = 3.6$

$v = \sqrt{3.6} = 1.897 m/s$

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Viefleur [7K]

Answer:900 feet

Explanation:

Given

Velocity $\left ( V_1\right )=20 mph\approx 29.334 ft/s$

it take 100 feet to stop

Using Equation of motion

$v^2-u^2=2as$

where

v,u=Final and initial velocity

a=acceleration

s=distance moved

$0-\left ( 29.334\right )^2=2\left (-a\right )\left ( 100\right )$

$a=\frac{29.334^2}{2\times 100}=4.302 ft/s^2$

When velocity is 60 mph $\approx 88.002 ft/s$

$v^2-u^2=2as$

$0-\left ( 88.002\right )^2=2\left ( -4.302\right )\left ( s\right )$

s=900.08 feet

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2 years ago

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A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.

Aleonysh [2.5K]

Answer: $53.31\°$ East of North

Explanation:

We have the following data:

Speed of the wind from East to West: $6.68 m/s$

Speed of the bee relative to the air: $8.33 m/s$

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the <u>Speed of the wind from East to West</u> (in the horintal part) and the <u>speed due North relative to the ground</u> (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

$sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}$

$sin \theta=\frac{6.68 m/s}{8.33 m/s}$

Clearing $\theta$ :

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2 years ago

A conducting rod (length = 80 cm) rotates at a constant angular rate of 15 revolutions per second about a pivot at one end. A un

Studentka2010 [4]

Answer:

3.62 V

Explanation:

L = 80 cm = 0.8 m

f = 15 rps

B = 60 m T = 0.060 T

ω = 2 x π x f = 2 x 3.14 x 15 = 94.2 rad/s

v = r ω

here, r be the radius of circular path. Here r = length of rod = L

v = 0.80 x 94.2 = 75.36 m/s

The motional emf is given by

e = B v L = 0.060 x 75.36 x 0.8 = 3.62 V

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2 years ago

If the gauge pressure of a gas is 114 kPa, what is the absolute pressure?

Anastasy [175]

Answer:

D. 214 kPa

Explanation:

The absolute pressure is given by:

$p = p_a + p_g$

where

p is the absolute pressure

$p_a \sim 100 kPa$ is the atmospheric pressure

$p_g$ is the gauge pressure

In this problem, we have

$p_g = 114 kPa$

So, the atmospheric pressure is

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Uranus is a gaseous planet and lies far from Sun and hence has large period of revolution. It takes 84 Earth years to revolve around Sun. This data indicates that Uranus resides in the outer region of the Solar System.

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