Answer:
Explanation:
Calcium chloride is a soluble salt which dissociates into calcium and chloride ions when dissolved in water.
CaCl₂(aq) ----> Ca²⁺(aq) + 2Cl⁻(aq)
Similarly, sodium oxalate when dissolved in water dissociates into sodium and oxalate ions.
Na₂CO₄(aq) ----> 2Na⁺(aq) + C₂O₄²⁻(aq)
However, in a double displacement reaction where the two solutions of the salts are mixed, the insoluble salt calcium oxalate is precipitated. The net ionic equation for the reaction is shown below:
Ca²⁺(aq) + C₂O₄²⁻(aq) ----> CaC₂O₄(s)
<span>carbon = 42.1%
hydrogen = 6.5%
oxygen = 51.4%
First lookup the molar mass of carbon, hydrogen, and oxygen.
mass of carbon = 12.0107
mass of hydrogen = 1.00794
mass of oxygen = 15.999
Now calculate the molar mass of each element in sucrose multiplying the atomic weight of each element by the number of times the element is used.
carbon = 12 * 12.0107 = 144.1284
hydrogen = 22 * 1.00794 = 22.17468
oxygen = 11 * 15.999 = 175.989
Calculate the molar mass of sucrose by adding the mass of each element used.
144.1284 + 22.17468 + 175.989 = 342.2921
Finally, calculate the percentage by mass of each element by dividing the mass used for each element by the total mass of sucrose.
carbon = 144.1284 / 342.2921 = 0.421068 = 42.1%
hydrogen = 22.17468 / 342.2921 = 0.064783 = 6.5%
oxygen = 175.989 / 342.2921 = 0.514149 = 51.4%</span>
Answer:
ΔH= 3KJ
Explanation:
The total heat absorbed is the total energy in the process, and that is in form of entalpy.
ΔH = q + ΔHvap, where q is the heat necessary for elevate the temperature of dietil ether. Suppose the initial temperature is room temperature (25ºC=298 K), then
q= 10g x2.261 J/gK x(310 K - 298K)= 271.32 J= 0.3 kJ
Then
ΔHvap = 10g C4H10O x (1 mol C4H10O/74.12 g C4H10O) x( 15.7 KJ/ 1 mol C4H10O) = 2.12 KJ
ΔH= 2.5KJ ≈ 3KJ
Density is the ratio of mass to the volume. The formula of density is:
-(1)
Density of carbon tetrachloride =
(given)
Mass of carbon tetrachloride =
(given)
Since, 
So, 
Substituting the values in formula (1):



Since, 
So, 
Hence, the volume of carbon tetrachloride is
.
2AgNO3+K2CrO4⇒Ag2CrO4(s)+2KNO3
Hence by mixing 0.0024M AgNO3 and 0.004M
K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with
0.0024M KN03 which is mixed with (0.004-0.0024/2)M, it can be 0.0028M, of K2Cr04