Question

A mass spectrometer, sketched below, is a device used to separate different ions. Such ions with a well-defined velocity vo enter through a slit into a region of uniform magnetic field B, where they follow a semicircular path until they strike the detector slit above the entry slit. The distance between the entry and the detector slit is d = 1.00 m.Chlorine ions of mass 35 amu (1 amu equals1.66×10-27 kg), carrying a charge of+1e enter the spectrometer with initial speedof vo = 2.30×105 m/s. Whatvalue of B is required for these ions to hit thedetector?

Answer 1

Answer:

The value of B is 0.167 T

Explanation:

Given data:

d = 1 m

r = 0.5 m

m = 35 amu = 35 * 1.66x10⁻²⁷ = 5.81x10⁻²⁶

q = 1e = 1.602x10⁻¹⁹

The value of B is equal to:

$B=\frac{mv}{qr} =\frac{5.81x10^{-26}*2.3x10^{5} }{1.602x10^{-19}*0.5 } =0.167T$