Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.
Answer:
3
Step-by-step explanation:
First, subtract 4 from both sides. When you do this, that leaves you with: 3x=9. Then, divide 9 by 3 to get x by itself. x=3
Answer:
(3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)
Step-by-step explanation:
(3 1/3)(5 1/4) =
= (3 1/3)(5 + 1/4)
= (3 1/3)(5) + (3 1/3)(1/4)
= (3 + 1/3)(5) + (3 + 1/3)(1/4)
= (3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)
Answer:
He invested 3,000 at 7% and 4,000 at 9%.
Step-by-step explanation:
From the information given, you can write the following equations:
x+y=7,000 (1)
0.07x+0.09y=570 (2)
You can solve for x in (1)
x=7,000-y (3)
Now, you can replace (3) in (1) and solve for "y":
0.07(7,000-y)+0.09y=570
490-0.07y+0.09y=570
0.02y=80
y=80/0.02
y=4,000
Finally, you can replace the value of "y" in (3):
x=7,000-4,000
x=3,000
According to this, the answer is that he invested 3,000 at 7% and 4,000 at 9%.
Let's calculate the value of angle A and B
sin(A) =-4/5 → sin⁻¹(- 4/5) = A → A = - 53.13
cos(B) = -5/13 → cos⁻¹ (- 5/13) = B → B = 112.62
tan (A+B) = sin(A+B)/cos(A+B) with A+B = -53.13 + 112.62 = 59.49
tan (A+B) = sin(59.49)/cos(59.49) = 0.86154/0.507688 = 1.6969.
(Answer H = 56/33 = 1.6969)
