For these lines, let
And for these, let
Now,
The vertices of
What is the lateral area of this regular octagonal pyramid? 84.9 cm² 120 cm² 169.7 cm² 207.8 cm²
2 answers:
Like jdoe0001 answered with 8[1/2(5)(6![8[ \frac{1}{2} (5)(6 \sqrt{2} )]](https://tex.z-dn.net/?f=8%5B%20%5Cfrac%7B1%7D%7B2%7D%20%285%29%286%20%5Csqrt%7B2%7D%20%29%5D)
if you solve the equation he/she gave you then you get 167.70562748. so your answer will be 167.7 cm^2
Check the picture below.
the lateral area, namely the area of the sides, in this case will be the area of all the triangular faces of the OCTAgonal pyramid, OCTA=8, so there are 8 of them.
now, each triangular face, has a base of 5 and a height of 6√2, so we simply get the area of each triangle and sum them up,
![\bf \stackrel{\textit{area of the 8 triangles}}{8\left[ \cfrac{1}{2}(5)(6\sqrt{2}) \right]} ](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%208%20triangles%7D%7D%7B8%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%285%29%286%5Csqrt%7B2%7D%29%20%5Cright%5D%7D%0A)
the lateral area, namely the area of the sides, in this case will be the area of all the triangular faces of the OCTAgonal pyramid, OCTA=8, so there are 8 of them.
now, each triangular face, has a base of 5 and a height of 6√2, so we simply get the area of each triangle and sum them up,
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