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Blababa [14]
2 years ago
12

What is the lateral area of this regular octagonal pyramid? 84.9 cm² 120 cm² 169.7 cm² 207.8 cm²

Mathematics
2 answers:
ahrayia [7]2 years ago
3 0
Like jdoe0001 answered with 8[1/2(5)(68[ \frac{1}{2} (5)(6 \sqrt{2} )] if you solve the equation he/she gave you then you get 167.70562748. so your answer will be 167.7 cm^2
Lesechka [4]2 years ago
3 0
Check the picture below.

the lateral area, namely the area of the sides, in this case will be the area of all the triangular faces of the OCTAgonal pyramid, OCTA=8, so there are 8 of them.

now, each triangular face, has a base of 5 and a height of 6√2, so we simply get the area of each triangle and sum them up,

\bf \stackrel{\textit{area of the 8 triangles}}{8\left[ \cfrac{1}{2}(5)(6\sqrt{2}) \right]}


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Patient A receives 3 times the amount of a certain medication as Patient B. The two doses add to 200 milligrams. What amount of
EastWind [94]

Answer:

Patient A - 150 mg

Patient B - 50 mg

Step-by-step explanation:

Since patient A gets three times more, 50 times 3 is 150. 150 plus 50 is 200, therefore, patient A gets 150 mg and patient B gets 50 mg. I hope this helps :)

5 0
1 year ago
In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.
Alona [7]
Y=600000(1+1.8%)^(x-2000)
So the population in 2012
Y=600,000×(1+0.018)^(2,012−2,000)
Y=743,232
6 0
1 year ago
Read 2 more answers
A car is traveling at a constant speed of 46 miles per hour. the formula for the distance traveled at the end of t hours is d=46
jonny [76]

d = 46t

  • First, let's find "d" for 7 hours.

           d = 46(7)

           d = 322 miles                          (7, 322)

  • Next, let's find "d" for 12 hours.

            d = 46(12)

            d =   552 miles                      (12, 552)

  • Finally, let's find "d" for 18 hours.

            d = 46(18)

           d = 828 miles                          (18, 828)    

3 0
2 years ago
Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
Lady bird [3.3K]
Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
         *1/2* sin(2*998a)*1/2*sin(2*999a) (there are 999 factors)
= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
1 year ago
Read 2 more answers
The fuel efficiency for a 2007 passenger car was 31.2 mi/gal. For the same model of car, the fuel efficiency increased to 35.6 m
Ierofanga [76]

We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.

We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.

Let represent the functions as d_{1}(x) and d_{2}(x)  where d_{1} and d_{2} represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

d_{1}(x)=31.2x \text{ and } d_{2}(x) = 35.6x

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.

The difference function will be:

f(x)=35.6x-31.2x\\
f(x)=4.2x

f(16)=4.2*16=67.2

Domain of this function is [0,16] and range is [0,67.2].

The graphs are shown below.


3 0
2 years ago
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