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Verdich [7]
2 years ago
12

Charlene is 8 years older than Aaron. the sum of their ages is 44. what are their ages?

Mathematics
1 answer:
san4es73 [151]2 years ago
8 0

Answer:

36

Step-by-step explanation:44-8=36

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Which is greater 9000cm or 2 km?
satela [25.4K]
Convert 2 km into cm

1 km = 100,000 cm

2 km = 200,000 cm

therefore 9,000 cm is greater
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Alexandra's bank statement shows a closing balance of $130.68. There are no outstanding checks or deposits. Her checkbook shows
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She has a difference of $2.75, she may have subtracted something wrong while balancing out the check book. 


5 0
2 years ago
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-79 = 7w + 3(4w – 1)​
vladimir1956 [14]

Hello! The answer to your question would be as followed:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    -79-(7*w+3*(4*w-1)=0

 -79 -  (7w +  3 • (4w - 1))  = 0

Pulling out like terms :

  Pull out like factors :

  -19w - 76  =   -19 • (w + 4)

 -19 • (w + 4)  = 0

Equations which are never true :

      Solve :    -19   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

     Solve  :    w+4 = 0

Subtract  4  from both sides of the equation :

                     w = -4

                  w = -4

5 0
2 years ago
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A wall in Maria’s bedroom is in the shape of a trapezoid. The wall can be divided into a rectangle and a triangle. Using the 45°
Radda [10]
A wall is in the shape of a trapezoid and it can be divided into a rectangle and a triangle. A triangle is with angles 45°- 45° - 90°. The hypotenuse of that triangle is 13√2 ft.Using the 45° - 45° - 90° theorem, sides of that triangle are in the proportion:x : x : x√2, and since that x√2 = 13√2 ( hypotenuse ),  x = 13.Therefore h = 13 ft.We can check it: c² = 13² + 13²,c² = 169 + 169c² = 338c = √ 338 = 13√2Answer: h = 13 ft

8 0
2 years ago
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Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D = {(x, y) |
Bas_tet [7]

Answer:

M=168k

(\bar{x},\bar{y})=(5,\frac{85}{28})

Step-by-step explanation:

Let's begin with the mass definition in terms of density.

M=\int\int \rho dA

Now, we know the limits of the integrals of x and y, and also know that ρ = ky², so we will have:

M=\int^{9}_{1}\int^{4}_{1}ky^{2} dydx

Let's solve this integral:

M=k\int^{9}_{1}\frac{y^{3}}{3}|^{4}_{1}dx

M=k\int^{9}_{1}\frac{y^{3}}{3}|^{4}_{1}dx      

M=k\int^{9}_{1}21dx

M=21k\int^{9}_{1}dx=21k*x|^{9}_{1}

So the mass will be:

M=21k*8=168k

Now we need to find the x-coordinate of the center of mass.

\bar{x}=\frac{1}{M}\int\int x*\rho dydx

\bar{x}=\frac{1}{M}\int^{9}_{1}\int^{4}_{1}x*ky^{2} dydx

\bar{x}=\frac{k}{168k}\int^{9}_{1}\int^{4}_{1}x*y^{2} dydx

\bar{x}=\frac{1}{168}\int^{9}_{1}x*\frac{y^{3}}{3}|^{4}_{1}dx

\bar{x}=\frac{1}{168}\int^{9}_{1}x*21 dx

\bar{x}=\frac{21}{168}\frac{x^{2}}{2}|^{9}_{1}

\bar{x}=\frac{21}{168}*40=5

Now we need to find the y-coordinate of the center of mass.

\bar{y}=\frac{1}{M}\int\int y*\rho dydx

\bar{y}=\frac{1}{M}\int^{9}_{1}\int^{4}_{1}y*ky^{2} dydx

\bar{y}=\frac{k}{168k}\int^{9}_{1}\int^{4}_{1}y^{3} dydx

\bar{y}=\frac{1}{168}\int^{9}_{1}\frac{y^{4}}{4}|^{4}_{1}dx

\bar{y}=\frac{1}{168}\int^{9}_{1}\frac{255}{4}dx

\bar{y}=\frac{255}{672}\int^{9}_{1}dx

\bar{y}=\frac{255}{672}8=\frac{2040}{672}

\bar{y}=\frac{85}{28}

Therefore the center of mass is:

(\bar{x},\bar{y})=(5,\frac{85}{28})

I hope it helps you!

3 0
2 years ago
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