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love history [14]
2 years ago
4

Megan has A quarters and B dimes with a total value of $1.95, where A and B are both counting numbers. How many different values

of A can Megan have?
Mathematics
1 answer:
hjlf2 years ago
5 0

Answer: The number of quarters can be 1, 3, 5 or 7

Step-by-step explanation:

Megan has A quarters and B dimes.

The value of a quarter is $0.25 and the value of a dime is $0.10

Then we have that:

A*$0.25 + B*$0.10 = $1.95

We want to know the different possible values of A.

Now, it is usefull to see the different multilpes of 0.25 (this is the odd multyples of 0.25) we only care for the ones that have a 5 in the undredth place, becauses we only can ad multiple of $0.10, so the 5 in the undredth place needs to come from this

Then the possible values of A are the odd numbers such that A*0.25 is smaller than 1.95, let's do the math:

0.25*1 = 0.25 (here 1.95 - 0.25 = 1.70, then B = 1.70/0.10 = 17) the pair is B = 17 and A = 1

0.25*3 = 0.75 (here 1.95 - 75 = 1.20, then B = 1.20/0.10 = 12) the pair is B = 12 and A = 3.

0.25*5 = 1.25 (here 1.95 - 1.25 = 0.70, then B = 0.70/0.10 = 7) the pair is B = 7 and A = 5

0.25*7 = 1.75 (here 1.95 - 1.75 = 0.20, then b = 0.20/0.10 = 2) The pair is B = 2 and A = 7

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<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
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