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m_a_m_a [10]
3 years ago
3

2772, 3663, 2970,4275, 5841, 3564 which of the numbers has to be excluded?

Mathematics
1 answer:
Vlad [161]3 years ago
8 0

Answer:4275

Step-by-step explanation:4275 will be removed because in the other numbers ,the numbers formed by the first two digits plus the number formed by the second two digits is 99 which does not happen in the case of 4275.

27=9 72=9

36=9 63=9

You might be interested in
RS=2x-8, ST= 11, RT= x+10
swat32

Answer:

X=7 ST=11 RT=17

Step-by-step explanation:

RT=RS+ST. RS= 2(7)-8. ST=11

X+10=2x-8+11. =14-8=6. RT= x+10

X+10=2x+3. RS=6. 7+10=17

10=x+3. RT=17

X=7

4 0
2 years ago
4C. Quintin is using the three different shaped
Sauron [17]

The smallest number of tiles Quintin will need in order to tile  his floor is 20

The given parameters;

  • number of different shapes of tiles available = 3
  • number of each shape = 5
  • area of each square shape tiles, A = 2000 cm²
  • length of the floor, L = 10 m = 1000 cm
  • width of the floor, W = 6 m = 600 cm

To find:

  • the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2

Area of the floor is calculated as;

A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2

The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

3 0
2 years ago
Angle EFG is 80°
Lana71 [14]

Answer:

X=80°

Step-by-step explanation:

Bc it’s in the same place as angle F

8 0
2 years ago
What is not a pair of equivalent fractions for 5/8 and 1/2
n200080 [17]
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18 
15/30: 5/10 OR 1/2 
45/60: 8/12 OR 4/6 

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number. 

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8. 
2/5 and 1/2: 2/5 and 2.5/5 
9/9 and 5/7: 9/9 and ~5.7/9 

Rewrite each in simple form: Find greatest common factor and divide. 

9/54: 1/6 
20/40: 1/2 
100/110: 10/11 

Are these fractions equivalent? 
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole. 


In what situation can you use multiplication to find equivalent fractions? 
I'm sorry but I do not understand this question. 
</span>Source(s):<span>I hope I  helped, seeing as I have graduated with a math degree.</span>
7 0
2 years ago
In △ABC,c=71, m∠B=123°, and a=65. Find b.<br><br> A. 101.5<br> B. 117.8<br> C. 123.0<br> D. 119.6
tia_tia [17]

Answer:

Option D

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. This means that the angle B is formed by the intersection of the lines a and c. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that c=71, B=123°, and a=65. Plugging in the values:

b^2 = 65^2 + 71^2 - 2(65)(71)*cos(123°).

Simplifying gives:

b^2 = 14293.0182932.

Taking square root on the both sides gives b = 119.6 (rounded to the one decimal place).

This means that the Option D is the correct choice!!!

8 0
2 years ago
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