Question

Which expressions can be simplified as StartFraction 625 Over n Superscript 12 Baseline EndFraction? Check all that apply.

Answer 1

Answer:

The short anwser is A and E

Step-by-step explanation:

Answer 2

Answer:

$A. (5n^{-3})^4\\E. (25n^{-6})^{2}$

Step-by-step explanation:

We are asked to determine which expressions out of the options simplifies to:

$\dfrac{625}{n^{12}}=625n^{-12}$

$A. (5n^{-3})^4=5^4*n^{-3*4}=625n^{-12}\\B. (5n^{-3})^{-4}=5^{-4}*n^{-3*-4}=\frac{1}{625}n^{12}\\C. (5n^{-4})^3=5^3*n^{-4*3}=125n^{-12}\\\\D. (25n^{-6})^{-2}=25^{-2}*n^{-6*-2}=\frac{1}{625}n^{12}\\\\E. (25n^{-6})^{2}=25^{2}*n^{-6*2}=625n^{-12}\\\\F. (25n^{2})^{-6}=25^{-6}*n^{2*-6}=\frac{1}{25^6}n^{-12}$

From the above results, we can see that only options A and E are equivalent to the given expression.