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slamgirl [31]
2 years ago
14

An archer tests various arrowheads by shooting arrows at a pumpkin that is suspended from a tree branch by a rope, as shown to t

he right. When struck head on by the arrow, the pumpkin
swings upward on the rope. The maximum angle that the rope makes with the vertical is different for each arrowhead that the archer tests. Each arrow, including its arrowhead, has the same
mass mand is shot with the same velocity vo toward the right
The arrowheads are made of different materials, however, and each behaves differently when it strikes the pumpkin, as described below.
- Embedded arrow Strikes the pumpkin and remains embedded, while the pumpkin swings to angle &emb
• Pass arrow Passes all the way through the pumpkin and continues traveling away from the archer, while the pumpkin swings to angle bass
- Bounce arrow. Bounces off the pumpkin back toward the archer, while the pumpkin swings to angle bounce
a Rank the three angles Gemb Bass and bounce from greatest to least in the spaces indicated below. Use"
three angles are the same, use the same number for their ranking
for the greatest angle, "2" for the next greatest and so on. If any two or all
_Gemb—_Bass_Bounce
b. In a clear, coherent, paragraph-length response that may also contain figures and/or equations, justify your ranking

Physics
1 answer:
erik [133]2 years ago
6 0

Answer:

Bounce 1 ,  pass 3,   emb2

Explanation:

(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle.  So it is  Bounce1, pass3, emb2.  

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Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
2 years ago
Consider a string of length 1.0 meter, fixed at both ends, with mass 100 grams and tension 100 newtons. part a give the number o
Bond [772]
To answer the problem we would be using this formula which isv = sqrt(T/(m/L)) 
v = sqrt(100 N / [(0.100 kg)/(1.0 m)]) 
v = 31.62 m/s 
v = fλ 
31.62 m/s = (95 Hz)(λ) 
λ = 0.333 m 
For every wavelength along a string there will be 2 antinodes. 
1.0 m / 0.333 m = 3 
3 * 2 = 6 antinodes 
6 + 1 = 7 nodes
4 0
2 years ago
Water floats on a liquid called "carbon tetrachloride." The two liquids do not mix. A light ray passing from water into carbon t
Oduvanchick [21]

Answer:

1.26

Explanation:

index  \: of  \: refraction \:  =  \:  \ \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) }

\frac{ \sin(45.0) }{ \sin(40.1) }

= 1.26

5 0
2 years ago
Alculate the potential difference if 20J of energy are transferred by 8C of charge.
sveta [45]

Answer:

V = 2.5 J/C

Explanation:

<u><em>Given:</em></u>

Energy = E = 20 J

Charge = Q = 8 C

<u><em>Required:</em></u>

Potential Difference = V = ?

<u><em>Formula:</em></u>

V = \frac{E}{Q}

<u><em>Solution:</em></u>

V = 20/8

V = 2.5 J/C

6 0
2 years ago
Your employer asks you to build a 18-cmcm-long solenoid with an interior field of 5.8 mTmT . The specifications call for a singl
andrezito [222]

Answer:

Explanation:

The magnetic field in a solenoid is

          B = μ₀ N / L I

Where N is the number of turns, L the solenoid length and I the current

          N = B L /  μ₀  I

Let's calculate

        N = 5.8 10⁻³ 0.18 / 4 π 10⁻⁷ 1

        N = 8.3 102 laps

        N = 831 laps

Let's find the solenoid length

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                L_solenoid = Turns * wire diameter

                L_ solenoid = 831 * 0.41 10--3

                L_solenoid = 0.3407 m

We see that two turns are needed in the wire to have a length of 0.18 m

5 0
2 years ago
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