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zepelin [54]
2 years ago
10

(a) Draw in radii OA, OB, OC and OD. Then, explain why OAB must

Mathematics
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

In the given circle, segments OA, OB, OC and OD are radius of the circle.

In other words, all those segments are congruent.

From that we can deduct that triangles OAB and OCD are isosceles triangles, because all segments are equal. That makes those triangles congruent, because they have the same sides.

From the congruence we can deduct that all corresponding internal angles inside those triangles are actually congruent, that's why angle OAB and ODC must be congruent.

Also, angles DOC and BOA are also congruent, which means their subtended arcs are also congruent, because they have the same radius, so mAB = mCD.

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The number of pounds of dog food that a pet store has is represented by the equation y = negative 15 x + 430, where x represents
sertanlavr [38]

Answer:  B) 115 pounds

Step-by-step explanation:

Because x is the number of days passed, after 21 days, x = 21.

y = -15(21)+430\\\\Multiply\\\\y = -315+430\\\\y=115

Hope it helps <3

6 0
2 years ago
Read 2 more answers
The graph of g(x) is the graph of f(x)=x+6 reflected across the x-axis. Which equation describes the function g?
nika2105 [10]
ANSWER

The correct answer is g(x)=-x-6

EXPLANATION

The mapping for reflection across the x-axis is given by (x,-y)

Given f(x)=x+6. We can let y=x+6

we can write the ordered pair (x,y) or (x,x+6) as the ordered pair of the preimage of f.

The image function will have the ordered pair (x,-y)

or

(x,-x-6).

That is, we negate all the y-coordinates.

Therefore

g(x)=-x-6.

4 0
2 years ago
Read 2 more answers
Solve the triangle. A = 19°, C = 102°, c = 6
GrogVix [38]
We know that

Law of sines established
a/sin A=b/sin B=c/sin C

then
a/sin A=c/sin C------------> a=c*sin A/sin C---------> a=6*sin 19/sin 102
a=1.91 units <span>≈2 units

A+B+C=180</span>°----------> B=180-(A+C)-----> B=1180-(19+102)
B=59°
a/sin A=b/sin B-----------> b=a*sin B/sin A----->2*sin 59/sin 19
b=5.27 units <span>≈5.3 units</span>

the answer is the option 
B = 59°, a ≈ 2, b ≈ 5.3 

7 0
2 years ago
Hariette would like to review the income and expenses that were actually paid last month so she can determine how much to set as
Brrunno [24]

Answer:

Hybrid basis

Step-by-step explanation:

There are different methods of accounting used by businesses depending on their peculiar needs. Below are the type of accounting methods:

- Cash basis is when revenues and expenses are recognised when cash is recieved or paid out.

-Accrual basis is when revenue and expenses are recognised when they are earned. For example if services are rendered to a client that will pay in a week's time, since service has already been given it is considered that the future payment has been earned.

- Modified basis combines elements of cash and accrual basis. For example considering short term assets like accounts receivable and accounts payable as cash items. Long term assets are recorded on accrual basis.

- Hybrid basis is used when cash and accrual methods are used for various expenses and tax. Mostly it is used for internal accounting purposes.

In this scenario Hariette would like to review the income and expenses that were actually paid last month. This requires a cash basis that shows actual amount recieved and paid last month. Account receivable and payable are not considered.

In setting aside money for tax she will employ accrual basis accounting. It is an expense that is estimated for future use.

So the hybrid basis is the method that will be most suitable.

5 0
2 years ago
A parabolic satellite dish reflects signals to the dish’s focal point. An antenna designer analyzed signals transmitted to a sat
ivolga24 [154]

Answer:

c=\frac{16}{39}

Step-by-step explanation:

The probability density function is :

f(x)=c(1-\frac{1}{16}x^{2})

With 0 < x < 3

To be a valid probability density function :

\int\limits^b_a {f(x)} \,dx=1

Where a < x < b

And also

f(x) ≥ 0 for a < x < b

Applying this to the probability density function of the exercise :

\int\limits^3_0 {c(1-\frac{1}{16}x^{2})} \, dx=1

c\int\limits^3_0 {(1-\frac{1}{16}x^{2})} \, dx=1

c(3-\frac{1}{16}\frac{3^{3}}{3})=1

c(\frac{39}{16})=1

c=\frac{16}{39}

We can verify by replacing ''c'' in the original probability density function and integrating :

\int\limits^3_0 {\frac{16}{39}(1-\frac{1}{16}x^{2})} \, dx=

=\frac{16}{39}.(3)-\frac{1}{39}.(\frac{3^{3}}{3})=\frac{16}{13}-\frac{3}{13}=\frac{13}{13}=1

Also, f(x) ≥ 0 for 0 < x < 3

4 0
2 years ago
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