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vagabundo [1.1K]
2 years ago
10

In ΔFGH, the measure of ∠H=90°, the measure of ∠G=64°, and HF = 72 feet. Find the length of FG to the nearest tenth of a foot.

Mathematics
1 answer:
a_sh-v [17]2 years ago
4 0

Answer:

<h3>ok line fg would be 80.107</h3>

Step-by-step explanation:

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Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent th
oksian1 [2.3K]
Equation represents the difference in the number of foreign and domestic stamps Malik collected: X-34=y

equation represents the total number of stamps Malik collected:
212 = X-34-y
so,
245= X-Y

Situation :
Y= X-34
X-Y= 245


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Rashid solved a fraction division problem using the rule “multiply by the reciprocal.” His work is shown below. Three-fourths di
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its b

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If 10x + 2 = 7, what is the value of 2x?
Julli [10]

For this case we have the following equation:

10x + 2 = 7

From here, we clear the value of x.

We have then:

10x = 7-2\\10x = 5\\x = \frac {5} {10}\\x = \frac {1} {2}

Then, we look for the value of 2x. We have then:

2x = 2 \frac {1} {2}\\2x = \frac {2} {2}\\2x = 1

Answer:

The value of 2x is given by:

2x = 1

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Really important please help #8
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2 years ago
Two samples each of size 20 are taken from independent populations assumed to be normally distributed with equal variances. The
Harlamova29_29 [7]

Answer:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

The system of hypothesis on this case are:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

We have the following data given:

n_1 =20 represent the sample size for group 1

n_2 =20 represent the sample size for group 2

\bar X_1 =43.5 represent the sample mean for the group 1

\bar X_2 =40.1 represent the sample mean for the group 2

s_1=4.1 represent the sample standard deviation for group 1

s_2=3.2 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

\S^2_p =\frac{(20-1)(4.1)^2 +(20 -1)(3.2)^2}{20 +20 -2}=13.525

And the deviation would be just the square root of the variance:

S_p=3.678

The statistic is givne by:

t=\frac{(43.5 -40.1)-(0)}{3.678\sqrt{\frac{1}{20}+\frac{1}{20}}}=2.923

The degrees of freedom are

df=20+20-2=38

And the p value is given by:

p_v =2*P(t_{38}>2.923) =0.0058

Since the p value for this cae is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true means for this case are significantly different

6 0
2 years ago
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