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tangare [24]
1 year ago
13

A car tire was inflated to 82.0 kPa in a repair shop where the temperature is 26.0 °c. What is the temperature of the gas in the

tire if the pressure in the tire increases to 87.3 kPa when it is out of the repair shop?
Chemistry
1 answer:
Vsevolod [243]1 year ago
4 0

Answer: The temperature of the gas in the tire if the pressure in the tire increases to 87.3 kPa is 45^0C

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=82.0kPa\\T_1=26.0^oC=(26.0+273)K=299K\\P_2=87.3kPa\\T_2=?

Putting values in above equation, we get:

\frac{82.0}{299}=\frac{87.3}{T_2}\\\\T_2=318K=(318-273)^0C=45^0C

Thus the temperature of the gas in the tire if the pressure in the tire increases to 87.3 kPa is 45^0C

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Explanation:

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1 year ago
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A solution was prepared by mixing 50.0 g
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Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

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mass of MgSO₄ = 50.0 g,

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Here we have to get the right answers which include the given phrase.

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Answer:  The new temperature is 10643 K

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