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tangare [24]
2 years ago
13

A car tire was inflated to 82.0 kPa in a repair shop where the temperature is 26.0 °c. What is the temperature of the gas in the

tire if the pressure in the tire increases to 87.3 kPa when it is out of the repair shop?
Chemistry
1 answer:
Vsevolod [243]2 years ago
4 0

Answer: The temperature of the gas in the tire if the pressure in the tire increases to 87.3 kPa is 45^0C

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=82.0kPa\\T_1=26.0^oC=(26.0+273)K=299K\\P_2=87.3kPa\\T_2=?

Putting values in above equation, we get:

\frac{82.0}{299}=\frac{87.3}{T_2}\\\\T_2=318K=(318-273)^0C=45^0C

Thus the temperature of the gas in the tire if the pressure in the tire increases to 87.3 kPa is 45^0C

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Sodium acetate spontaneously crystallizes out of a supersaturated solution upon standing or upon the addition of a seed crystal.
AlekseyPX

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Option (c) is correct.

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As sodium acetate crystallizes out spontaneously therefore it is associated with \Delta S>0.

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6 0
2 years ago
g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole
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-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

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Answer:

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Explanation:

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3 0
2 years ago
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