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Ludmilka [50]
2 years ago
7

Leading edge flaps can be used to decrease (or eliminate) the leading edge suction peak at a desired lift coefficient. When airf

oils are designed for cruise performance, however, a better strategy is to design an airfoil that produces the correct lift with no suction peak using a cambered airfoil (i.e. without including leading edge flaps). To see that this is possible, we will consider the NACA 44XX airfoils. Also, p is the location of the maximum camber and is second digit/10. Apply thin airfoil theory to answer the following questions: (a) Determine the angle of zero lift for the 44XX airfoils (b) Determine the angle at which the suction peak is eliminated. We will call this the design angle of attack for the 44XX airfoils (c) What is the design lift coefficient for the 44XX airfoils (i.e. the lift coefficient at the design angle of attack)?
Physics
1 answer:
Alik [6]2 years ago
5 0

Answer:

An investigation is made to determine the performance of simple thin airfoils in the slightly supersonic flow region with the aid of the nonlinear transonic theory first developed by von Kármán[1]. Expressions for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are developed in terms of a transonic similarity parameter. Aerodynamic coefficients are calculated in similarity form for the flat plate and asymmetric wedge airfoils, and curves are plotted. Sample curves for a flat plate and a specific asymmetric wedge are plotted on the usual coordinate grid of Cl, Cd,andCmc/4versus angle of attack and Cl versus Mach Number to illustrate the apparent features of nonlinear flow.

Explanation:

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B⃗ is kept constant but the coil is rotated so that the magnetic field, B⃗ , is now in the plane of the coil. How will the magne
s344n2d4d5 [400]

Answer:

<u>The flux decreases because the angle between B⃗ and the coil's axis changes.</u>

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Explanation:

The flux through the coil is given by a dot product, between the magnetic field and the vector representing the area of the coil.

\Phi = \vec{B}\cdot \vec{S} = BScos(\theta)

The latter vector has direction perpendicular to the plane in which the area of the coil is, and magnitude equal to the area of the coil. As in the attached image, the vector S is the vector respresenting the area of the coil.

Therefore, the flux will be maximum when the vector S is in the same direction as B, and will be zero when they are perpendicular.

Now, if <em>the coil is rotated so that the magnetic field is in the plane of the coil </em>then, the vectors S and B are perpendicualr, and there will not be net magnetic flux, that is, the flux will decrease.

3 0
2 years ago
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In an experiment to measure the wavelength of light using a double slit, it is found that the fringes are too close together to
Mandarinka [93]

Answer:

halve the slit separation

Explanation:

As we know that

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d denotes the distance in the middle of two slits

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2 years ago
A force of 5000 n is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a young's modulus of 125 x 1
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Por definicion tenemos que
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2 years ago
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A bag containing originally 60 kg of flour is lifted through a vertical distance of 9 m. While it is being lifted, flour is leak
Art [367]

Answer:

The total work done is 5997.6 J

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As per the question:

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Vertical distance, h = 9 m

Mass lost, m' = 12 kg

To calculate the amount of work done:

Lost mass is proportional to the square root of the distance covered while lifting:

m' ∝ \sqrt{h}

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Work done is given by:

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3 0
2 years ago
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