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Anit [1.1K]
2 years ago
10

During an experiment, an investigator gently abrades the skin from the flank of a mouse, creating a 1 × 2-cm skin window. A glas

s cover slip is then placed over the area so that cells attracted to the site attach to the cover slip for assessment. Two hours later, an extravasation of cells from the vasculature is noted on the cover slip. Which of the following complement components is the direct cause of the enhanced vascular permeability and chemoattraction in the abraded skin area in this experiment? (A) C1q (B) C4b (C) C5a (D) C7 (E) C9
Chemistry
1 answer:
VLD [36.1K]2 years ago
8 0

Answer: The complement components that is the direct cause of the enhanced vascular permeability and chemoattraction in the abraded skin area in this experiment is C5a. The correct option is C.

Explanation:

When the investigator gently abrades the skin from the flank of a mouse, creating a 1 × 2-cm skin window, the investigator caused a mild tissue damage which leads to a complex series of events resulting in the repair of the damaged tissue. These events are collectively called an INFLAMMATION. Inflammation can therefore be defined as the reaction of vascularized living tissue to local injury.

There are many compounds that triggers specific aspects of inflammation and they are collectively called inflammatory mediators. An example is the Complement component 5a. It has the following functions in mediating inflammatory response:

- enhances vascular permeability

- it has the ability to attract other cells to the site of the abraded skin area (a chemoattractant).

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AleksAgata [21]

Volume of tank = 6.9 m^{3} (given)

Since, 1 m = 3.28 ft

So,  

1 m^{3} = 35.287 ft^{3}

For 6.9 m^{3}:

6.9\times 35.287 ft^{3} = 243.4803 ft^{3}

The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

243.4803 ft^{3} \simeq 243.5 ft^{3}

Hence, volume in ft^{3} is 243.5.

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2 years ago
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If one has a solution of 0.10 m silver nitrate and it is diluted by a factor of two, what is the new concentration
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7 0
2 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C  

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7 0
2 years ago
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steposvetlana [31]

Answer: The \Delta H_{rxn} for the given chemical reaction is -175.51 kJ/mol

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Enthalpy change for the reaction of he given chemical reaction is given by:

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Putting the values in above equation, we get

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