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Fynjy0 [20]
2 years ago
8

Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds

Physics
2 answers:
Aliun [14]2 years ago
7 0
Hope it cleared your doubt.

xenn [34]2 years ago
3 0
We know, a = v₂ - v₁ / t
Here, (v₂-v₁) = 33 - 11 = 22 m/s
t = 10 s

Substitute their values, 
a = 22/10
a = 2.2 m/s²

In short, Your Answer would be 2.2 m/s²

Hope this helps!
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Read 2 more answers
A Porsche challenges a Honda to a 200-m race.Because the Porsche's acceleration of 3.5 m/s2 is larger than the Honda's 3.0 m/s2,
Blizzard [7]

Answer:

Honda won by 0.14 s

Explanation:

We are given that

Distance =S=200 m

Initial velocity of Honda=u=0m/s

Initial velocity of Porsche=u'=0m/s

Acceleration of Honda=3.0m/s^2

Acceleration of Porsche's=3.5m/s^2

Time taken by Honda  to start=1 s

s=ut+\frac{1}{2}at^2

Substitute the values

200=0(t)+\frac{1}{2}(3)t^2

200=\frac{3}{2}t^2

t^2=\frac{200\times 2}{3}=\frac{400}{3}

t=\sqrt{\frac{400}{3}}=11.55s

Time taken by Honda=11.55 s

Now, time taken by  Porsche

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t^2=\frac{200\times 2}{3.5}

t=\sqrt{\frac{400}{3.5}}=10.69 s

Total time taken by Porsche=10.69+1=11.69 s

Because it start 1 s late

Time taken by Honda is less than Porsche .Therefore, Honda won and

Time =11.69-11.55=0.14 s

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