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alexgriva [62]
2 years ago
3

What do the symbols tell you about the conditions of the reactions shown to the right? Check all of the boxes that apply.

Chemistry
2 answers:
lesantik [10]2 years ago
4 0

Answer:

A and D

A. The products and reactants of both reactions are gases.

D. A catalyst is used for reaction 2.

Explanation: got it right on edge

dybincka [34]2 years ago
3 0

Answer:

A and D

Explanation:

thank me later

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Which of the following solutions is a buffer?A) A solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M HCl.B) A s
kumpel [21]

Answer:

D

Explanation:

solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M NaOH Can resist pH change when there is little addition of either acid or base, hence it is a buffer solution

7 0
2 years ago
A student dissolved 4.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution
mihalych1998 [28]

Answer:

0.08097 grams of nitrate ions are there in the final solution.

Explanation:

Moles of cobalt(II) nitrate ,n= \frac{4.00 g}{245 g/mol}=0.01633 mol

Volume of the cobalt(II) nitrate solution, V = 100.0 mL = 0.1 L

Molarity=\frac{n}{V(L)}

Let the molarity of the solution be M_1

M_1=\frac{0.01633 mol}{0.1 L}=0.1633 M

A students then takes 4 .00 mL of M_1 solution and dilute it to 275 ml.

M_1=0.1633 M

V_1=4.00 mL

M_2=? (molarity after dilution)

V_2=275 mL (after dilution)

M_1V1=M-2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{0.1633 M\times 4.00 mL}{275 mL}=0.002375 M

Molarity of the of solution after dilution is 0.002375 M.

Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)

1 mol of cobalt(II) nitrate gives 2 moles of nitrate ions. Then 0.002375 M solution of cobalt (II) nitrate will give:

[NO_3^{-}]=\frac{2}{1}\times 0.002375 M=0.004750 M

Moles of nitrate ions = n

Volume of the solution = 275 mL = 0.275 L

Molarity of the nitrate ions = [NO_3^{-}]=0.004750 M

[NO_3^{-}]=\frac{n}{0.275 L}

n = 0.001306 mol

Mass of 0.001306 moles of nitrate ions:

0.001306 mol × 62 g/mol= 0.08097 g

0.08097  grams of nitrate ions are there in the final solution.

4 0
2 years ago
the height of a column of mercury in barometer is 754.3mm. what us the atmospheric pressure in atm. in kPa.
Aleksandr-060686 [28]
1 atm = 760mmHg
754.3 mmHg / 760 mmHg * 1atm = 0.99 atm
760 mmHg = 101.3 KPa
754.3 mmHg/ 760mmHg *101.3 KPa = 100.54 KPa

Hope this helps!
8 0
2 years ago
Using the mass of the proton 1.0073 amu and assuming its diameter is 1.0×10−15m, calculate the density of a proton in g/cm3.
icang [17]

Answer : 3.2 X 10^{15} g/cm^{3}

Explanation :  To convert amu i.e. atomic mass unit in grams we have the conversion factor as 1 amu = 1.66054 X 10^{-24} g

we know the mass of the proton is 1.0073 amu

So converting it into grams we have to multiply;

1.0073 amu X  1.66054 X 10^{-24} g/amu = 1.673 X 10^{-24} g

Now, Volume = 1/6πd³ as diameter is given as 1.0 X 10^{-15} m converting it to cm will require to multiply with 100

∴ Volume  = 1/6π (1.0 X 10^{-15}mX 100 cm / 1 m)^{3}

Hence, volume =  5.236 X 10^{-40} cm^{3}

Therefore, Density = mass / volume

∴ Density =  1.673 X 10^{-24} g / 5.236 X 10^{-40} cm^{3}

Therefore, Density will be 3.2 X 10^{15} g/cm^{3}.

6 0
2 years ago
Read 2 more answers
Why are the concentrations of [H3O+] and [OH−] equal in pure water?
kotegsom [21]

Answer : The correct option is, (A) [H_3O^+]=[OH^-] because one of each is produced every time an [H^+] transfers from one water molecule to another.

Explanation :

As we know that, when the two water molecule combine to produced hydronium ion and hydroxide ion.

The balanced reaction will be:

HOH+HOH\rightarrow H_3O^++OH^-

Acid : It is a substance that donates hydrogen ion when dissolved in water.

Base : It is a substance that accepts hydrogen ion when dissolved in water.

From this we conclude that, the hydrogen ion are transferred from one water molecule to the another water molecule to form hydronium ion and hydroxide ion. In this reaction, one water molecule will act as a base and another water molecule will act as an acid.

Hence, the correct option is, (A)

3 0
2 years ago
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