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Lyrx [107]
2 years ago
10

Write a two to four sentence conclusion statement explaining how the potential energy diagram is used to identify if the reactio

n is endothermic or exothermic, if heat was released or absorbed, and why the sign of enthalpy change was positive of negative. There should be a conclusion statement for each graph.
Chemistry
1 answer:
LenKa [72]2 years ago
8 0

Answer:

Check Explanation

Explanation:

First Sentence

The Heat of a reaction is given as the heat content/heat of formation/enthalpies of the products minus the heat content/heat of formation/enthalpies of the reactants.

ΔH = H(products) - H(reactants)

Second Sentence

If the potential energy diagram has the product(s) having a higher potential energy than the reactant(s), then the reaction is an endothermic reaction (this is why the reaction absorbs heat from the surroundings to try to make up for the lack of potential energy of the reactants) and the sign on the enthalpy change is visibly positive since H(products) > H(reactants)

Third Sentence

If the potential energy diagram has the reactant(s) having a higher potential energy than the product(s), then the reaction is an exothermic reaction (this is why the reaction releases heat to the surroundings to try to take care of the higher potential energy of the reactants) and the sign on the enthalpy change is visibly negative since H(reactants) > H(products).

Hope this Helps!!!

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400 mL of hydrogen are collected over water at 18 C and a total pressure of 740 mm of mercury. (Vapor pressure of H2O at 18 C=15
MrRa [10]

Answer:

a)15.5 mmHg is the partial pressure of water vapor.

b) 724.5 mmHg is the partial pressure of hydrogen gas.

Explanation:

Total pressure of gases = T = P = 740 mmHg

Vapor pressure of the water = p_1=15.5 mmHg

Partial pressure of the hydrogen gas = p_2=?

Partial pressure of the water = p_1=15.5 mmHg

15.5 mmHg is the partial pressure of water vapor.

Using Dalton's law of partial pressure:

P=p_1+p_2

740 mmHg=15.5 mmHg+p_2

p_2=740 mmHg-15.5mmHg =724.5 mmHg

724.5 mmHg is the partial pressure of hydrogen gas.

6 0
2 years ago
How many moles of O are in 2.45 moles of H2CO3?​
Irina-Kira [14]

Answer:

7.35 moles of oxygen

Explanation:

First of all, for 1 mole of H₂CO₃ we have 3 moles of oxygen (can be deduced from the chemical formula of the acid), then the moles of oxygen in 2.45 mole of the compound, which are given in the question, from the carbonic acid will be:  

If in        1 mole of H₂CO₃ we have 3 moles of oxygen

The in    2.45 moles of H₂CO₃ we have X moles of oxygen

X = ( 3 × 2.45 ) / 1 = 7.35 moles of oxygen

3 0
2 years ago
For each of the following substituents, indicate whether it withdraws electrons inductively, donates electrons by hyperconjugati
AveGali [126]

Answer:

a. withdraws electrons inductively

b. donates electrons by hyperconjugation

c. donates electrons by resonance

d.  withdraws electrons inductively

Explanation:

a.  The bromide ion is a highly electronegative ion (in the halide series). Electronegative substituents on acids increase the acidity by inductive electron withdrawal method. The higher the electronegativity of a substance, the greater the acidity. The halogens have this order of electronegativity:

F > Cl > Br>I

b.  The carboxyl groups have a stabilization of the sigma and pi bonds. This is achieved through a special delocalization of electrons.  Because of the delocalization, hyperconjugation is the result effect.

c. The NHCH₃ group has a highly electonegative nitrogen atom that pulls the electron cloud towards itself. In this case, it withdraws electrons inductively. As a result, it donates electrons by resonance.

d. The OCH₃ group has a highly electonegative oxygen atom. This oxygen atom withdraws electron cloud towards itself. As a result, it withdraws electrons inductively.

3 0
2 years ago
A 50.0 mL Erlenmeyer flask filled with 1-hexanol has a mass of
Iteru [2.4K]
Yes it is correct for that answer
4 0
2 years ago
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Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.
Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}

Converting moles of boric acid to mass:

0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}}   = 6.183 g

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.


5 0
2 years ago
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