Describe the structure of ammonium lauryl sulfate. Refer to the given diagram. Your answer should include the type of bonding, t
he elements contained, and the size and shape of the molecule. Write a short paragraph.
*diagram is a molecular diagram of ammonium lauryl sulfate
*diagram is a molecular diagram of ammonium lauryl sulfate
1 answer:
Answer:
The compound contains lauryl sulfate and ammoium ions. Lauryl sulfate contains lauric acid (in black and white) , the fatty acid formed by the covalent bonds between C-C attached to hydrogens, and sulfate ions attached to lauric acid (in red) with C-S covalent bond. Sulfer is attached to oxygen by covalent bonds. In Ammonium ions, N is surrounded by four hydrogen atoms.
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To solve this question, we need to use the Avogadro's Number, which is a constant first discovered by Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are 6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:
So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent 14,12 moles of Na₂SO₃
Have a nice day!
To solve this question, we need to use the Avogadro's Number, which is a constant first discovered by Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are 6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:
So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent 14,12 moles of Na₂SO₃
Have a nice day!
Answer : The concentration of Si in kilograms is,
Explanation :
As we are given that, the concentration of Si in an Fe-Si alloy is 0.25 wt% that means:
Weight of Si = 0.25 g = 0.00025 kg
Weight of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg
Density of Si =
Density of Fe =
Now we have to calculate the concentration in kilograms of Si per cubic meter of alloy.
Concentration of Si in kilograms =
Concentration of Si in kilograms =
Now put all the given values in this expression, we get:
Concentration of Si in kilograms =
Concentration of Si in kilograms =
Thus, the concentration of Si in kilograms is,