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Katyanochek1 [597]
2 years ago
4

A storage box for skis measures 0.45 m high,0.45 m wide, and 1.7 m long. What is the volume

Mathematics
1 answer:
koban [17]2 years ago
6 0

Answer:

Option A. 0.37 cubic m

Step-by-step explanation:

Hope this helps :)

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The graph below shows the line of best fit for data collected on the number of cell phones and cell phone cases sold at a local
DiKsa [7]

Answer:

C

Step-by-step explanation:

The equation of a line is given by

and

slope (m) is given by:

Where (x_1,y_1) are the first set of point in the line and (x_2,y_2) is the second set of point

Let's take 2 points arbitrarily. (0,0) & (25,20)

Let's plug it and find the equation:

Now

C is the correct answer.

6 0
2 years ago
[URGENT} What is the domain of the function shown in the graph?
kirill115 [55]
Anwser: C
X must be greater or equal to 3
4 0
2 years ago
Last year your professor wanted to study the pattern in class grades. The following table contains a sample of grades collected
Maslowich

Answer:

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Step-by-step explanation:

<u>Mean:-</u>

The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻

                                                                                                                           mean =  \frac{64+80+75+98+75}{5}

mean (x⁻ ) = 78.4

The mean of the given data = 78.4

<u>Median:</u>

The median is found by ordering the set from lowest to highest and finding the exact middle.

64 ,75, 80, 98

The middle term of the given data set = \frac{75+80}{2} =77.5

<u>Mode :</u>

The mode is the most common repeated number in a data set.

64 ,75, 75, 80, 98

in data the most common number = 75

<u>Conclusion</u>:-

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

   

8 0
2 years ago
Allie works for Canton Water Works. Her annual salary is $75,964.
Solnce55 [7]
I think it’s gonna be B
8 0
2 years ago
PI-3.
Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

x=2q_1+1

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

x=3q_2+1

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

x=7q_6

This means x-1 is divisible by 2, 3, 4, 5 and 6 without remainder, so

x-1=2\cdot 3\cdot 2\cdot 5n=60n

Hence,

x=60n+1, \ n\in N

The smallest amount of money they could have raised is $301, because

x=60\cdot 5+1=301 is divisible by 7.

Now, the number x=60n+1 should be divisible by 7 and must be greater than 500.

So,

60n+1>500\\ \\60n>499\\ \\n>8

When n = 9,

x=60\cdot 9+1=541 is not divisible by 7.

When n = 10,

x=60\cdot 10+1=601 is not divisible by 7.

When n = 11,

x=60\cdot 11+1=661 is not divisible by 7.

When n = 12,

x=60\cdot 12+1=721 is divisible by 7.

B. The least amount of money they could have raised is $721

7 0
2 years ago
Read 2 more answers
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