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stepladder [879]
2 years ago
6

Calculate the resistance of the filament of a 40 Watt lightbulb if it draws 3 amperes when 120V are impressed across it​

Physics
1 answer:
frosja888 [35]2 years ago
4 0

Answer:

40 ohms

Explanation:

resistance = voltage/current

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A damped harmonic oscillator consists of a block of mass 2.5 kg attached to a spring with spring constant 10 N/m to which is app
Cerrena [4.2K]

Answer:

0.5% per oscillation

Explanation:

The term 'damped oscillation' means an oscillation that fades away with time. For Example; a swinging pendulum.

Kinetic energy, KE= 1/2×mv^2-------------------------------------------------------------------------------------------------------------(1).

Where m= Mass, v= velocity.

Also, Elastic potential energy,PE=1/2×kX^2----------------------------------------------------------------------------------------------------------------------(2).

Where k= force constant, X= displacement.

Mechanical energy= potential energy (when a damped oscillator reaches maximum displacement).

Therefore, we use equation (3) to get the resonance frequency,

W^2= k/m--------------------------------------------------------------------------------------(3)

Slotting values into equation (3).

= 10/2.5.

= ✓4.

= 2 s^-1.

Recall that, F= -kX

F^2= (-0.1)^2

Potential energy,PE= 1/2 ×0.01

Potential energy= 0.05 ×100

= 0.5% per oscillation.

6 0
2 years ago
An object is released from rest near and above Earth’s surface from a distance of 10m. After applying the appropriate kinematic
Damm [24]

Answer:

v_y = 12.54 m/s

Explanation:

Given:

- Initial vertical distance y_o = 10 m

- Initial velocity v_y,o  = 0 m/s

- The acceleration of object in air = a_y

- The actual time taken to reach ground t = 3.2 s

Find:

- Determine the actual speed of the object when it reaches the ground?

Solution:

- Use kinematic equation of motion to compute true value for acceleration of the ball as it reaches the ground:

                             y = y_o + v_y,o*t + 0.5*a_y*t^2

                             0 = 10 + 0 + 0.5*a_y*(3.2)^2

                             a_y = - 20 / (3.2)^2 = 1.953125 m/s^2

- Use the principle of conservation of total energy of system:

                             E_p - W_f = E_k

Where,                  E_p = m*g*y_o

                             W_f = m*a_y*(y_i - y_f)      ..... Effects of air resistance

                             E_k = 0.5*m*v_y^2

Hence,                  m*g*y_o - m*a_y*(y_i - y_f) = 0.5*m*v_y^2

                             g*(10) - (1.953125)*(10) = 0.5*v_y^2

                             v_y = sqrt (157.1375)

                            v_y = 12.54 m/s

4 0
2 years ago
What is the depth of the crater if the time is 6.3 s? An astronaut stands by the rim of a crater on the moon, where the accelera
ollegr [7]

Complete Question

An astronaut stands by the rim of a crater on the moon, where the acceleration of gravity is 1.62 m/s2. To determine the depth of the crater, she drops a rock and measures the time it takes for it

to hit the bottom. If the time is 6.3 s, what is the depth of the crater?

Answer:

The depth is 32 m

Explanation:

From the question we are told that

  The  time is  t =  6.3 s

  The acceleration due to gravity is  g =  1.62 \  m/s^2

 

Generally from kinematic equation

    s = ut + \frac{1}{2}  - at^2

Here the u is the initial  velocity and the value is  0 m/s

      s = 0 + \frac{1}{2}  - (1.62) * (6.3)^2

        s = 32 \ m

   

8 0
2 years ago
A girl and a boy are riding on a merry-go-round that is turning at a constant rate. the girl is near the outer edge, and the boy
lutik1710 [3]
In order to clearly qualify this problem, we use relationships between linear displacement (x) and angular displacement (theta). The relationship would be, x= r*theta, where r is the radius. From here, you can deduce that the smaller the radius, the larger the angular displacement. Hence, the boy that is closer to the center would experience greater angular displacement.
5 0
2 years ago
Read 2 more answers
Explain how climbing a mountain is similar to hiking from the equator to one of the poles
Igoryamba

Explanation:

  • Climbing a mountain is similar to hiking from the equator to the pole because in both cases temperature decreases.
  • The higher you go, the cooler it becomes.
  • For a certain elevation, there is particular drop in temperature. High altitudes offers cooler temperatures.
  • The equator receives a huge insolation and the sun is overhead there.
  • It implies that the temperature is always high around the equatorial region.
  • As one increases latitude, the temperature drops and its is coldest at the pole.
  • In both cases, temperature drops and it gets colder.

Learn more:

Temperate and tropics brainly.com/question/10856870

#learnwithBrainly

8 0
2 years ago
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