Answer:
Option c (Upper tailed) is the correct choice.
Step-by-step explanation:
Given that:
The average attendance is:
= 74,900
We will have to test:
⇒ 
or,

Verses,
⇒ 
or,

The other given alternatives aren't connected to the given scenario. So the above is the correct one.
Answer:
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Step-by-step explanation:
Consider the provided information.
The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.
Mean = μ= 12.5
σ = 0.58
n = 15
![\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]](https://tex.z-dn.net/?f=%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm%202%280.58%29%5C%5C%5Cmu%5Cpm2%5Csigma%3D12.5%5Cpm1.16%5C%5C%5Cmu%5Cpm2%5Csigma%3D%5B11.34%2C%2013.66%5D)
Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.
Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.
Since there are two dice, the total possible outcome is 36.
Hence, the probability of getting one number each is 1/36
Hence, the principal used a fair method because each result is an equally likely possible outcome.
Option B is correct.
Step-by-step explanation:
1.901
hope this helps.
Answer:
c)3u-3v-w
Step-by-step explanation: