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2 years ago

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Exactly 253.0 J will raise the temperature of 10.0 g of a metal from 25.0 °C to 60.0 °C. What is the specific heat capacity of t

he metal?
a. 0.723 J/(g. °C)

b. 1.38 J/(g°C)

C 12.2 J/g °C)

d. 60.5J/g - °C)

e. None of these

1 answer:

xxMikexx [17]2 years ago

7 0

Answer:a. 0.723 J/(g. °C)

Explanation:

Q = mCΔT

where,

Q- Quantity of heat supplied-= 253.0j

m - mass of substance=10g

C - specific heat capacity=?

ΔT - change in temperature = 60 - 25 = 35°C

Imputing values, we have ,

Q = mCΔT

C = Q/(mΔT) = 253.0/ ( 10 x 35 ) = 0.7228 rounded to ---> 0.723 J/(g. °C)

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