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qaws [65]
2 years ago
3

Two identical speakers are 3.50 m and 5.20 m from a listener. What is the lowest frequency (n = 1) that would cause constructive

interference there? PLS HELP!
Physics
1 answer:
solong [7]2 years ago
6 0

Path length difference = 5.20 - 3.50 = 1.70m.

The longest wavelength (hence lowest frequency) that gives destructive interference has path length difference= λ/2.

λ/2 =1.70

λ = 3.40m

Taking speed of sound as v = 340m/s:

f = v/λ = 340/3.40 = 100Hz.

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Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t) = 2.6667t2, where t i
Eddi Din [679]

Answer:

averaage speed  is  v = 13 feet / s

Explanation:

 The average speed is the ratio of the distance traveled in a given time interval, let's calculate the distance that the body travels in the two instants of time that give us

   

 t = 1 s

       d (1) = 2.6667 1²

       d (1) = 2.6667 feet

 t = 4 s

       d (4) = 2.6667 4²

       d (4) = 42.6672 feet

Let's calculate the speed

       v = Δx / Δt

       v = (42.6672 -2.6667) / (4-1)

       v = 40/3

        v = 13.33335 feet / s

        v = 13 feet / s

6 0
2 years ago
A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.
Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = 6.5*10^{4}\ m/s

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity [\theta] = 15 degree.

We are asked to calculate the magnetic force experienced by the charged  particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force \vec F=q(\ \vec V \times \vec B)

                        i.e F = =qVBsin\theta

                                   =6.8*6.5*10^{4}*1.4*sin15

                                   =61.88*10^{4}sin15

                                   =61.88*10^4*0.2588\ N

                                   =16.016*10^4\ N

                                   =1.6*10^5\ N

Hence, the force experienced by the charged particle is C i.e 1.6*10^5 N

                                   

             

4 0
2 years ago
Read 2 more answers
Two narrow, parallel slits separated by 0.85 mm are illuminated by 600 nm light, and the viewing screen is 2.8 m away from the s
AURORKA [14]

Answer:

Phase difference = pi/4 radians

Explanation:

Given:

- The wavelength of incident light λ = 600 nm

- The split separation d = 0.85 mm

- Distance of screen from split plane L = 2.8 m

Find:

What is the phase difference between the two interfering waves on a screen, at a point 2.5 mm from the central bright fringe?

Solution:

- The phase difference can be evaluated by determining the type of interference that occurs at point y = 2.5 mm above central order. We will use the derived results from Young's double slit experiment.

                                  sin ( Q ) = m*λ /d  

                                  m = d*sin(Q) / λ

- Where, m is the order number and angle Q is the angle for mth order of fringe from central bright fringe.

                                  r = sqrt ( L^2 + 0.0025^ )

Where, r is the distance from split to the interference bright fringe.

                                  r = sqrt(2.8^ + 0.0025^) = 2.8

                                  sin(Q) = 0.0025 / 2.8

Hence.                        m = 0.00085*0.0025 / 2.8*(600*10^-9)

                                   m = 1.26

- We know that constructive interference would occurred at m = 1 and destructive interference @ m = 1.5. They have a phase difference of pi/2 radians.

- The order number lies in between constructive and destructive interference i.e m ≈ 1.25 then the corresponding phase difference = 0.5*(pi/2).

Answer:                  Phase difference = pi/4 radians

6 0
2 years ago
A cat falls from a table of height 1.3 m. What is the impact speed of the cat?
guapka [62]
Use this formula
Vf = sqrt(2gh) 
5 0
2 years ago
There is an electromagnetic wave traveling in the -z direction in a standard right-handed coordinate system. What is the directi
wlad13 [49]

Answer: The direction of the electric field, E→, is pointed in the +y direction.

Explanation:

One can use the right hand rule to illustrate the direction of travel of an electromagnetic and thereby get the directions of the electric field, magnetic field and direction of travel of the wave.

The right hand rule states that the direction of the thumb indicate the direction of travel of the electromagnetic wave (<em>in this case the -z direction</em>) and the curling of the fingers point in the direction of the magnetic field  B→ (<em>in this case the +x direction</em>), therefore, the electric field direction E→ is in the direction of the fingers which would be pointed towards the +y direction.

6 0
2 years ago
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