A car speeds up from 18.54 m/s to 29.52 m/s in 13.84 s. The acceleration of the car is:
2 answers:
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Answer:
aₓ = 0 , ay = -6.8125 m / s²
Explanation:
This is an exercise that we can solve with kinematics equations.
Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.
x axis
vₓ = v₀ₓ = 1.10 m / s
aₓ = 0
y axis
initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration
= v_{oy} -ay t
ay = (v_{oy} -v_{y}) / t
ay = (0 -10.9) / 1.6
ay = -6.8125 m / s²
the sign indicates that the acceleration goes in the negative direction of the y axis
Answer:
a.3.20m
b.0.45cm
Explanation:
a. Equation for minima is defined as:
Given ,
and
:
#Substitute our variable values in the minima equation to obtain :
#draw a triangle to find the relationship between and
.
#where
Hence the screen is 3.20m from the split.
b. To find the closest minima for green(the fourth min will give you the smallest distance)
#Like with a above, the minima equation will be defined as:
, where
given that it's the minima with the smallest distance.
#we then use to calculate
=4.5cm
Then from the equation subtract from
:
Hence, the distance is 0.45cm