To find the mean of the data, you will combine all values together and then spread them all out evenly to create one value that represents the data.
In math this involves adding the data together and then dividing the sum by how many pieces of data there are.
682 + 601 + 744 + 674 + 701 + 790 + 676 + 638 + 773 = 6279
6279/9 = 697.66...
The rounded credit score is 698 (Choice A).
When you think about it. It's actually quite easy.
The number are the amount of miles, and the variables are the amount of hours. So we would just have to multiply them. So, by putting the number together we would be able to multiply them once we have the numbers for the variables. Since we dont have them, we can just make the inequality. It says that car 1 traveled at LEAST that of car 2. Showing that car 1 may have traveled farther. SOOOOO........ the inequality should look like this:
165x <span>≥ 175y</span>
Let the score of cowboys is x
and giants make score 9 which is twice less than the cowboys score so
giants score will be = 2x -9
and packers scored 14 more than giants that is (2x - 9) + 14
now sum of their scores is equal to 81 it means:
x + (2x - 9) + (2x -9) + 14 = 81
x + 2x - 9 + 2x - 9 + 14 = 81
5x = 81 + 4
5x = 85
x = 17
packers scored = (2x - 9) + 14
= 2 (17) -9 + 14
=38 + 5 = 43 points
Answer:
a) 1+2+3+4+...+396+397+398+399=79800
b) 1+2+3+4+...+546+547+548+549=150975
c) 2+4+6+8+...+72+74+76+78=1560
Step-by-step explanation:
We know that a summation formula for the first n natural numbers:
1+2+3+...+(n-2)+(n-1)+n=\frac{n(n+1)}{2}
We use the formula, we get
a) 1+2+3+4+...+396+397+398+399=\frac{399·(399+1)}{2}=\frac{399· 400}{2}=399· 200=79800
b) 1+2+3+4+...+546+547+548+549=\frac{549·(549+1)}{2}=\frac{549· 550}{2}=549· 275=150975
c)2+4+6+8+...+72+74+76+78=S / ( :2)
1+2+3+4+...+36+37+38+39=S/2
\frac{39·(39+1)}{2}=S/2
\frac{39·40}{2}=S/2
39·40=S
1560=S
Therefore, we get
2+4+6+8+...+72+74+76+78=1560
Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if 
here;
Thus;
∴
Hence, we can conclude that r(t) and s(t) are parallel.
