Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².

Quadratic formula is

'a' is the coefficient of x^2 = 4
'b' is the coefficient of x = 2
'c' is the constant = -1
Now we plug in all the values in quadratic formula



The above one is the substitution of values of a,b,c in quadratic formula.
7 3/4 × 3/4 = So u add 3×3=9
Then add 4×4=16 Give you 9/16
Then you add that 7 you left out with 9/16
But just the 9 not the 16
7 × 9 = 63 And your answer is 63/16
Hope i help :-)
If you double the dimensions of the tank, you also double the volume of the tank.
Therefore, volume of the new touch tank = 2000 x 2 = 4000 ft^3