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Dmitry_Shevchenko [17]
2 years ago
12

A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the ca

lorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.
** I know someone already answered this on another post, but I think their answer is incorrect** I did it and think I have the right answer, but I want to double check it. Thanks!
Chemistry
1 answer:
disa [49]2 years ago
7 0

Answer:

Explanation:

Heat lost by metal = mass x specific heat x fall in temperature

= 74 x S x ( 94 - 32 )

= 4588 S

heat gained by water = mass x specific heat x rise in temperature

= 120 x 1 x ( 32 - 26.5 )   ( specific heat of water is 1 cals / gm )

= 660

Heat lost = heat gained

4588S = 660

S = .14 cal /gm .

Specific heat of metal = .14 cal  / gm

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What is the molarity of a solution made by dissolving 8.60 g of a solid with a
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Answer:

1.43 M

Explanation:

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Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

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8 0
2 years ago
identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet,
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