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timofeeve [1]
2 years ago
15

1. How many moles of tin are needed to react with 3.5 moles of hydrogen fluoride?

Chemistry
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

1.75 mole of Sn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Sn + 2HF —> SnF2 +H2

From the balanced equation above,

1 mole of Sn reacted with 2 moles of HF.

Therefore, Xmol of Sn will react with 3.5 moles of HF i.e

Xmol of Sn = 3.5/2

Xmol of Sn = 1.75 mole

Therefore, 1.75 mole of Sn is needed to react with 3.5 moles of HF

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M = number of moles of solute / volume of solution in liters

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molar mass of CHCl3 = 119.37 g/mol

number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol

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mole fraction of solute, X solute

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number of moles of solution = number of moles of solute + number of moles of solvent

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</span>
7 0
2 years ago
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